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2 years ago

Help pleaseeeeeeeeeeeeeee

Mathematics

2 answers:

TEA [102]2 years ago

4 0

Answer:

54m2

Step-by-step explanation:

Cut the shape into two - from the 9m length. One has 3m by 8m(ie 5m + 3m) dimensions, and the other 6m(ie 9m - 3m) by 5m dimensions.

Taking area of first one=24m2,then area of the second =30m2.

To get area of whole shape, we add both areas=54m2

NB:Area=l×b

gladu [14]2 years ago

3 0

The answer to this question is 54m2

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Anestetic [448]

Answer:

Acceleration when time is $2 \ sec$ = $-\frac{5}{4} \ m/s^2$

Distance $s=9-\frac{9}{t}$

Distance travelled between $t=1$ and $t=3$ is $6\ m$

Step-by-step explanation:

Velocity $V=1+\frac{9}{t^2} \ \ \ when \ \ 1\leq t\leq 3$

Acceleration(a): Rate of change of velocity.

$a=\frac{dV}{dt} =1-\frac{18}{t^3}$

at $t=2$

$a=1-\frac{18}{8} \\=1-\frac{9}{4} \\=-\frac{5}{4}$

$a=-\frac{5}{4} \ m/s^2$

Distance(s):

$V=\frac{ds}{dt}\\\\\frac{ds}{dt}=1+\frac{9}{t^2}\\\\Integrate\ both\ sides\\\\s=1-\frac{9}{t}+k\\\\ k\ is\ a\ constant\\\\Given\ s=6\ when\ t=3\\\\6=1-\frac{9}{3}+k\\\\ k=8\\\\Hence\ s=1-\frac{9}{t}+8\\\\ s=9-\frac{9}{t}$

Distance between $t=1 \ and \ t=3$

$=s(3)-s(1)\\\\=(9-\frac{9}{3})-(9-9) \\\\=6 \ m$

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