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natka813 [3]
3 years ago
8

What are some fun games to play on your computer

Mathematics
1 answer:
sasho [114]3 years ago
7 0
Papas pizzeria!! Haha
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Need help with thisss
frozen [14]

9514 1404 393

Answer:

  cos(x) = 0.6

Step-by-step explanation:

First, we need to find UQ.

  UQ = UP·cos(y°) = UP·√(1 -sin²(y°)) = (26 cm)√(1 -25/169) = (26 cm)(12/13)

  UQ = 24 cm

Then TQ is ...

  TQ = 1/3UQ = 1/3(24 cm) = 8 cm

And cos(x°) is ...

  cos(x°) = √(1 -sin²(x)) = √(1 -64/100)

  cos(x°) = 6/10 = 3/5

  cos(x°) = 3/5 = 0.6

7 0
3 years ago
Someone please help with this geometry question!!!
ahrayia [7]

What is the number down their?

6 0
3 years ago
Evaluate <br>1.3 + 12 + 2.1 =​
GenaCL600 [577]

Answer:

The answer is 15.4

Step-by-step explanation:

hope this helps

1.3 + 12 =13.3+2.1=15.4

3 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
What three-dimensional figure is generated?
Elan Coil [88]
It should be a cylinder generated by the rotation. Take a piece of paper or book and rotate it with one edge as the center, and visualize what shape it makes. Doing something like this will be the best way to understand what shape it forms.
7 0
2 years ago
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