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2 years ago

Which angle has a measure equal to the sum of m∠SQR and m∠QRS?

Mathematics

1 answer:

ser-zykov [4K]2 years ago

6 0

Answer:

QSR

Step-by-step explanation:

Same letters so its the answer

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A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

Tomtit [17]

Answer:

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

$=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3$

4 0

3 years ago

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7.1 is 10 times smaller than

Aleks [24]

7.1 is ten times smaller than 71

8 0

3 years ago

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A square has a perimeter of 40cm what is the length of each side

docker41 [41]

Answer:

length of each side : 10 cm

Step-by-step explanation:

all sides of squares are equal

thus, 4 sides = 40 cm

1 side = 40/10 cm

1 side = 10 cm

5 0

3 years ago

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Need help with this question!!

alexira [117]

Answer:

is number 2

Step-by-step explanation:

3 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a

VMariaS [17]

(a) If $y(t)$ is the mass (in mg) remaining after $t$ years, then $y(t) = y(0) e^{kt}=100e^{kt}.$

$y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}$

(b) $y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}$

(c)
$100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}$

3 0

3 years ago