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Deffense [45]
3 years ago
10

What is: x(x+3)(x+3)=0 Please help!! I will give 10 points!

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0

\text{Find the values of x:}\\\\x(x+3)(x+3)=0\\\\\text{We know for the x outside of the parenthesis, it has to equal 0}\\\\\text{For the x inside the parenthesis, we would need to equal it to 0 and }\\\text{solve for x}\\\\x+3=0\\\\x=-3\\\\\text{There are two of them, so we would have two of the same answer}\\\\\boxed{\text{x= 0 or x = -3 or x = -3}}

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julia-pushkina [17]
Lets solve the equalities first.
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5 0
3 years ago
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31. Jamie works at pizza hut. She makes $30 a day, plus $2 for each pizza she delivers. She earned $50
Mashcka [7]

Answer:

10

Step-by-step explanation:

30+2+2+2+2+2+2+2+2+2+2

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6 0
3 years ago
Help me please. I don’t understand this math. My math teacher is mean. :(((((
Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is 5cm^3

And length is \frac{3}{4} and width is 1\frac{1}{3}

That is V=5cm^3[/tex] , l=\frac{3}{4}cm and w=1\frac{1}{3}cm

We have the  volume of the rectangular prism V=lwh cubic centimeter

V=lwhcm^3

Substituting the values in above formula

5=\frac{3}{4}\times 1\frac{1}{3}\times h

5=\frac{3}{4}\times \frac{4}{3}\times h

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Rewritting as below

h=5cm

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5 0
3 years ago
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Help please. (attachment below)
Marina86 [1]
B. seven minutes - because that is when the slope of the line is flat, which means he isn't moving.
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3 years ago
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A company introduces a new product for which the number of units sold S is
KonstantinChe [14]
(a) The "average value" of a function over an interval [a,b] is defined to be 

(1/(b-a)) times the integral of f from the limits x= a to x = b. 

Now S = 200(5 - 9/(2+t)) 

The average value of S during the first year (from t = 0 months to t = 12 months) is then: 

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12 

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12 

This equals 200/12 * (5t -9ln(2+t)) 

Evaluating this with the limits t= 0 to t = 12 gives: 

708.113 units., which is the average value of S(t) during the first year. 


(b). We need to find S'(t), and then equate this with the average value. 

Now S'(t) = 1800/(t+2)^2 

So you're left with solving 1800/(t+2)^2 = 708.113 

<span>I'll leave that to you</span>
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