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Maru [420]
2 years ago
13

Eight trucks hold a total of 10 and 1/2 tons of cargo. Half the trucks are

Mathematics
1 answer:
RUDIKE [14]2 years ago
6 0

Answer:

2 large trucks = 14 tons of cargo

1 small truck = 3½ tons of cargo

Equation: x + 2x = 10½

Step-by-step explanation:

8 trucks - 4 large trucks, 4 small trucks

small truck = x

large truck = 2x

First, you need to find out how much cargo 1 large truck and 1 small truck can hold.

x + 2x = 10½

3x = 21/2

3x = 10.5

x = 3.5 or 3½

1 small truck can hold 3½ tons of cargo, and 1 large truck can hold 7 tons of cargo.

Next, you need to substitute and find how much cargo 4 large trucks can hold. <em>(Remember: 1 large truck = 7 tons of cargo)</em>

2x

= 2(7)

= 14 tons of cargo

4 large trucks can hold 14 tons of cargo.

Finally, you know that one small truck equals 3½ tons of cargo.

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Solve the equation then check your solution 5p=140 <br> A)28<br> B)700<br> C)-28<br> D)26
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Answer:

p=28

Step-by-step explanation:

5p=140

To to find the value of p divide both sides by 5 (5p/5 and 140/5)

p=28!


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A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

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3 years ago
What is the domain of f(x) = 5^x - 7?
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Answer:

D

Step-by-step explanation:

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Seven hotdogs and four hamburgers cost $13. Four hotdogs and seven hamburgers cost $14.50. How much does one hamburger cost and
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Answer:

hotogs=$1.50  hamburgers=$1

Step-by-step explanation:

h=hotdog b=hamburger

7h+4b=13

4h+7b=14.5

(7h+4b=13)-4b

4h+7b=14.5

 

h=-0.57b+1.86

4h+7b=14.5

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3 years ago
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