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Feliz [49]
3 years ago
15

Find the area of the triangle

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

297.5 in

Step-by-step explanation:

Area of triangle = Base times Height divided by 2.

Base=35

Height=17

So, 35 x 17 = 595

595/2=297.5

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Dan invests £800 into his bank account.
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£160

Step-by-step explanation:

Ammount he receives per year times 4.

800 x 0.05 x 4

= £160

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2 years ago
Identify the coefficients and variables in rst-12v
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5 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
Add 280.00 +21.40 +6.30 +.41 = 308.71, I don't know where the 7 was added though
Vitek1552 [10]
I m getting 308.11, there is an additional 0.60 that is added, maybe your source is wrong, or there is a copying error.
8 0
3 years ago
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