B. 23
Hope this helps!!!!!!
![4*e^{2x} -3 = 12](https://tex.z-dn.net/?f=%204%2Ae%5E%7B2x%7D%20-3%20%3D%2012%20)
Step 1:
Here we have -3 in subtraction on the left side, so when we take it to the right we apply opposite operation of subtraction that is addition.
![4*e^{2x} = 12+3](https://tex.z-dn.net/?f=%204%2Ae%5E%7B2x%7D%20%3D%2012%2B3%20)
![4*e^{2x} = 15](https://tex.z-dn.net/?f=%204%2Ae%5E%7B2x%7D%20%3D%2015%20)
Step 2:
Next we have 4 in multiplication on left side, so dividing right side by 4,
![e^{2x} = 15/4](https://tex.z-dn.net/?f=%20e%5E%7B2x%7D%20%3D%2015%2F4%20)
![e^{2x} = 3.75](https://tex.z-dn.net/?f=%20e%5E%7B2x%7D%20%3D%203.75%20)
Step 3:
taking log on both sides
![ln ( e^{2x}) = ln(3.75)](https://tex.z-dn.net/?f=%20ln%20%28%20e%5E%7B2x%7D%29%20%3D%20ln%283.75%29%20)
![{2x} =ln 3.75](https://tex.z-dn.net/?f=%20%7B2x%7D%20%3Dln%203.75%20)
Step 4:
Dividing right side by 2,
x= ln (3.75) /2 = 0.66088
Answer : x = 0.66088..
The answer is
X=7
Have a nice day <3
Answer:
The Figure for Right triangle is below,
Therefore , 15 unit length represents BC.
Step-by-step explanation:
Given:
Consider a right triangle ABC, Such that
![\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}](https://tex.z-dn.net/?f=%5Ccos%20A%3D%5Cdfrac%7B15%7D%7B17%7D%5C%5C%5C%5C%5Ctan%20A%3D%5Cdfrac%7B8%7D%7B15%7D)
To Find:
BC = ?
Solution:
In Right Angle Triangle ABC, Cosine and Tangent identity
![\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\](https://tex.z-dn.net/?f=%5Ccos%20A%20%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20adjacent%20to%20angle%20C%7D%7D%7BHypotenuse%7D%5C%5C)
![\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}](https://tex.z-dn.net/?f=%5Ctan%20A%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20opposite%20to%20angle%20A%7D%7D%7B%5Ctextrm%7Bside%20adjacent%20to%20angle%20A%7D%7D)
BUT,
....Given
On Comparing,
Adjacent side to angle A = AB = 15
Opposite side to angle A = BC = 8
Hypotenuse = AC =17
Also Pythagoras theorem is Satisfies,
![(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}](https://tex.z-dn.net/?f=%28%5Ctextrm%7BHypotenuse%7D%29%5E%7B2%7D%20%3D%20%28%5Ctextrm%7BShorter%20leg%7D%29%5E%7B2%7D%2B%28%5Ctextrm%7BLonger%20leg%7D%29%5E%7B2%7D)
![(\textrm{Hypotenuse})^{2} = 17^{2}=289](https://tex.z-dn.net/?f=%28%5Ctextrm%7BHypotenuse%7D%29%5E%7B2%7D%20%3D%2017%5E%7B2%7D%3D289)
![(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289](https://tex.z-dn.net/?f=%28%5Ctextrm%7BShorter%20leg%7D%29%5E%7B2%7D%2B%28%5Ctextrm%7BLonger%20leg%7D%29%5E%7B2%7D%3D15%5E%7B2%7D%2B8%5E%7B2%7D%3D289)
The Figure for Right triangle is below,
Therefore , 15 unit length represents BC.