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yawa3891 [41]
2 years ago
9

If a die is rolled it may have 1, 2, 3, 4, 5, or 6 showing, and each outcome is equally likely to occur. If three dice are rolle

d, what is the probability that the sim of the three numbers showing is at least 15
Mathematics
1 answer:
Phoenix [80]2 years ago
8 0

Answer:

3/16

Step-by-step explanation:

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Solve (2 - x)^2 < 4/25
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Answer:

8/5 < x< 12/5

Step-by-step explanation:

(2 - x)^2 < 4/25

Take the square root of each side

sqrt((2 - x)^2)  <±sqrt( 4/25)

Make two equations

2-x < 2/5    2-x > -2/5

Subtract 2 from each side

2-x-2 < 2/5 -2          2-x-2  > -2/5-2

-x < 2/5 -  10/5             -x > -2/5  - 10/5

-x < -8/5                         -x > -12/5

Multiply by -1, remembering to flip the inequality

x> 8/5                   x < 12/5

8/5 < x< 12/5

5 0
3 years ago
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QUESTION 14
Mice21 [21]

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2 years ago
8. f(n) = f(n-1) + 1; f(1) =<br>win​
DanielleElmas [232]

Answer:

we are looking for F

but in the question it stated that f(n) and at the end it also stated that f(1) so n=1

Step-by-step explanation:

we are using BODMAS

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3 years ago
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vovikov84 [41]
$37.70; $580 x 6.5% x 1 = $37.70
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