Answer:
3/4
Step-by-step explanation:
Since we have two points, we can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 5 - -1)/( 4 - -4)
= ( 5+1)/(4+4)
= 6/8
= 3/4
Answer:
4.9
Step-by-step explanation:
Let us first find the frequency from the cumulative frequency.
Starting number is same.
To find the next number subtract the previous number from that number.
i.e first number = 0.15
Second number = 0.45 – 0.15 = 0.3
Third number = 0.60 – 0.45 = 0.15
Fourth number = 0.85 – 0.60 = 0.25
Fifth number = 1.00 – 0.85 = 0.15
Value Frequency Value × Frequency
1 0.15 0.15
3 0.3 0.9
5 0.15 0.75
7 0.25 1.75
9 0.15 1.35
Number of frequency = 1
Total value = 0.15 + 0.9 + 0.75 + 1.75 + 1.35 = 4.9
Mean =
= 4.9
Answer:
A. "an arithmetic sequence with a common difference (d) of -6."
B. 33 hours
C. ![a_n=a_1+(n-1)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%28n-1%29d)
D. See below
Step-by-step explanation:
A.
Since the sequence lessens by 6, this is an arithmetic sequence with a common difference (d) of -6.
B.
The formula for term of arithmetic sequence is:
![a_n=a_1+d(n-1)](https://tex.z-dn.net/?f=a_n%3Da_1%2Bd%28n-1%29)
Wher a_1 is the first term and d is the common difference. Since we want to find after 33 weeks, we plug in 33 into n:
![a_{33}=225 + (-6)(33-1)\\a_{33}=33](https://tex.z-dn.net/?f=a_%7B33%7D%3D225%20%2B%20%28-6%29%2833-1%29%5C%5Ca_%7B33%7D%3D33)
She will have left 33 hours
C.
We will use the arithmetic sequence term formula written above, that is:
![a_n=a_1+(n-1)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%28n-1%29d)
THis gives us the amount of hours left after a certain number of weeks.
D.
We plug in 40 into n and find the hours left:
![a_{40}=225+(40-1)(-6)\\a_{40}=225-234\\a_{40}=-9](https://tex.z-dn.net/?f=a_%7B40%7D%3D225%2B%2840-1%29%28-6%29%5C%5Ca_%7B40%7D%3D225-234%5C%5Ca_%7B40%7D%3D-9)
THis term is NEGATIVE, which means that Greta will not have to work 40 weeks to fulfill the target of 225 hours. She needs to work less.
I believe the answer is C