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1 year ago

10

Find the lcm, of x, 2x, 3x

1 answer:

zysi [14]1 year ago

4 0

Since x, 2x, 3x contain numbers and variables, it takes two steps to find the LCM. Find the LCM for the numerical part 1; 2; 3; then find the LCM for the variable part x¹ ; x¹; x¹.

The LCM is the smallest number by which all numbers are divided without leaving a remainder.

List the prime factors of each number.
Multiply each factor the greatest number of times that occurs in any of the numbers.

The number 1 is not a prime number because it only has one positive factor, which is itself.

not cousin.

Since 2 has no divisors other than 1 and 2.

2 is a prime number.

Since 3 has no divisors other than 1 and 3.

3 is a prime number.

The least common multiple LCM of 1,2,3 is the result of multiplying all the prime factors the greatest number of times that appear in each term.

2 × 3

Multiply 2 by 3.

6

The factor for x¹ is x itself.

x¹ = x

The Least Common Multiple LCM of x¹ ; x¹; x¹ is the result of multiplying all the prime factors the greatest number of times that appear in each term.

x

The LCM for x;2x;3x is the numerical part 6 multiplied by the variable part.

6x ====> Answer

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What is the value of 2/3(x -6) -y , when x= 9 and y=5/6?

ANTONII [103]

Answer:

Ã=7/6

Step-by-step explanation:

<em>2/3(x -6) -y </em>

<h3><em>put the value of x= 9 and y=5/6 </em></h3>

=2/3(9-6)-5/6

=2/3×3-5/6

=2/1-5/6

=12-5/6

=7/6

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7 0

2 years ago

Read 2 more answers

The LCM of two numbers is 48. The number one in the ratio 2:3. Then Sum of the numbers is:

Oksi-84 [34.3K]

Answer:

40

Step-by-step explanation:

Let the numbers be 2x and 3x

Then their L.C.M. = 6x

BUT also their LCM=48

6x=48

x=48/6

x=8

So,

First number=2x=2x8=16

Second number=3x=3x8=24

The numbers are 16 and 24.

Hence required sum =(16+24)=40

So none of the options are correct

6 0

3 years ago

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pentagon [3]

Answer:

Answer

Step-by-step explanation:

The answer is d because if you at 17 to 197 you'll get 203

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2 years ago

Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2

kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is $x=-83.25$

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

$(y - k)^{2}=4p(x - h)$

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

$x=y^{2} +18y-2$

Convert to standard form

$x+2=y^{2} +18y$

$x+2+81=y^{2} +18y+81$

$x+83=(y+9)^{2}$

so

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

so

The vertex is the point (-83,-9)

step 2

we have

$x+83=(y+9)^{2}$

<em>Find the value of p</em>

$4p=1$

$p=1/4$

<em>Find the focus</em>

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

$x=h-p$

substitute

$x=-83-1/4$

$x=-83.25$

6 0

3 years ago

What is the property of <br><br> a(ab)+(ab)b

BARSIC [14]

Communitive Property

5 0

3 years ago

Read 2 more answers