Solve. 4(x+2)^2=16 HELP PLSSSS

Mathematics

1 answer:

serious [3.7K]2 years ago

4 0

Answer:

x=0; x=-2

Step-by-step explanation:

so first you do (x+2)^2 which is x^2+2x+4

4x^2 +8x +16 = 16

Subtract 16 from both sides

4x^2 +8x = 0

factor out 4x:

4x(x+2) = 0

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R varies inversely as v2 if r=120 when v=1 ,find r when v=10

makvit [3.9K]

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➷ r = k/v^2

Substitute the values in:

120 = k/1^2

Multiply both sides by 1^2 to find k

k = 120

Substitute new values in:

r = 120/10^2

Solve:

r = 1.2

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6 0

3 years ago

I still don’t understand can someone give a helping hand?

Fofino [41]

Answer:

Step-by-step explanation:

A, B, C, and D, are all functions. the " { " is saying that those functions can are different at different points. For A the function is $A= -x-2$ when $x< 2$ and then $A=x+4$ when $x\geq -2$ . At the point $x=-2$ you can see that the function on the graph is going in two different directions but it stops at $x=-2$ .

Based on the graph you can see that the line on the left has a slope of -1 and if it kept going it would cross the y-axis at $y=-2$ , therefore the equation for the first line is $y =-x-2$ when $x$