3 years ago

Solve. 4(x+2)^2=16 HELP PLSSSS

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

Answer:

x=0; x=-2

Step-by-step explanation:

so first you do (x+2)^2 which is x^2+2x+4

4x^2 +8x +16 = 16

Subtract 16 from both sides

4x^2 +8x = 0

factor out 4x:

4x(x+2) = 0

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