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Ksivusya [100]
2 years ago
13

Determine the stopping distance of a car with an initial speed of 29.97 m/s, a human reaction time of 1s, and an acceleration of

-4 m/s^2.
Mathematics
2 answers:
Rudik [331]2 years ago
8 0

Answer:

5/18 m/s?

Step-by-step explanation:

deff fn [24]2 years ago
6 0

Answer:

Step-by-step explanation:

is that the qustion

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Beth sold half of her comic books and then bought nine more. She now has 28. With how many did she begin?
tankabanditka [31]

Answer:

She had 38!

Step-by-step explanation:

28-9 is 19 then just multiply that by two which is 38

8 0
2 years ago
Read 2 more answers
Complete the statements using the drop-down menus. The line perpendicular to the y-axis through the point (–4, –2) is . The slop
Vlad [161]

Answer:

Y=-2, 0

Step-by-step explanation:

EDG 2020

3 0
3 years ago
Find the value of the missing coefficient a in the equation y = a(x - 3)(x + 5) if the graph goes through the point (1, -6)
horrorfan [7]

Answer:

3

Step-by-step explanation:

you have to solve for x then you can find the coeeffiecnt

3 0
2 years ago
Find the angle measure of PQR
sineoko [7]

Answer:

<em>64 degrees</em>

Step-by-step explanation:

When you have the SRQ angle, you can easily solve for PQR. Luckily, we're given that QRP and PRS are 32 and 84, respectively. Adding this together gives you 116. 116*2 = 232 and 360-232 = 128, and 128/2 = 64.

<em>Please Mark Brainliest if this helps!</em>

8 0
2 years ago
Plz do this question if you did I will very appreciated you. plz.​
Nastasia [14]

The area formula of a circle is r^{2} × π.

With that being said, we can solve both problems!

Starting with part A:

-The radius we know is 21cm. From there, we can substitute in our formula with the new value.

21^{2} x π

From there, we can square our radius:

(21 x 21) x π

(441) x π

And finally, we can multiply by pi to get our answer.

(441) x π

1385.44236023

Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.

The second part can be followed with the same process, hopefully you understand the concept enough to where you're comfortable solving problems like this on your own. Feel free to reach out if you have any further trouble!

<em>Hope this helped! :)</em>

5 0
2 years ago
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