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Nookie1986 [14]
2 years ago
15

What

Mathematics
1 answer:
Shkiper50 [21]2 years ago
8 0
Drawing a king is 1/4 and drawing a black card is 26/52
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What is the least common denominator of the fraction 4 over x plus the fraction 2 x over x minus 1 plus the fraction x plus 3 ov
Leya [2.2K]

If we consider x having any other value then 0,1 or 2 then the answer is b.2x(x-1)

8 0
3 years ago
How many distinct factors does 75 have?
OlgaM077 [116]

Answer:

The distinct factors of 75 are 1, 3, 5, 15, 25, 75.

Step-by-step explanation:

Please mark brainliest and have a great day!

7 0
3 years ago
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The volume of a cubic box is 10 to the power of 6 cubic millimeters. Write the volume in standard form
Vinil7 [7]
1 \times 10^{6} mm^{3}
5 0
3 years ago
How any is?<br> 8m + 27 = 2m - 3 <br> with procedure and testing
givi [52]
8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
3 0
3 years ago
Read 2 more answers
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
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