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ololo11 [35]
3 years ago
6

PLEASE HELP find the area

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

31.4 is the area..heres how I'm positive because if u multiply the full circle it wouldn't be half so 6.28xthats

KIM [24]3 years ago
8 0
78.5

Formula: (3.14)(5•5)
Pie • radius squared
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Tom has 120 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house
mezya [45]

Answer:

a) Function A(x) =  (60*x - 1/2*x²)

b)Side length     x = 60 m      the other side   y = 30 m

c) A (max)  = 1800 m²

Step-by-step explanation:

Area of rectangular garden with length  " x " and wide "y"

A = x*y        

Perimeter of rectangular area ( only three sides 2*y and 1*x)

P(r)  = 2*y + x

P(r) = 120 = 2*y + x

y = ( 120 - x ) /2

Area of the garden as function of x is

A(x) = [( 120 - x ) /2]*x          ⇒     A(x) = (60*x - 1/2*x²)

Taking derivatives on both sides of the equation:

A´(x) = 60 - x

A´(x)  = 0            60  -  x  = 0

x = 60 m

Then

y = ( 120  -  x ) / 2                ⇒   y = (120 - 60 )/2

y = 30 m

A(max) = 30 * 60

A(max) = 1800 m²

8 0
4 years ago
How do I write a numerical expression for 5 times the sum of 3 and 4
vitfil [10]
5(3+4)first you would add 3 and 4 and then multiply 5 to it

6 0
3 years ago
34% as a fraction in its similiest form
sesenic [268]

Answer:

17/50

Step-by-step explanation:

34%

34/100

17/50

its correct

3 0
3 years ago
Read 2 more answers
6 points
soldier1979 [14.2K]
He has 576.50 now in his account
8 0
4 years ago
Find how many solutions there are to the given equation that satisfy the given condition.
den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi  ≥ 0 and yi \epsilon {\displaystyle \mathbb {Z} }  )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

\bigg(^{27}_{4} \bigg)

∴

The number of nonnegative integer solution is \bigg(^{27}_{4} \bigg)

= \dfrac{27!}{4!(27-4)!}

= \dfrac{27!}{4!(23)!}

= \dfrac{27\times 26\times 25\times 24 \times  23 !}{4\times 3\times 2\times 1(23)!}

= \dfrac{27\times 26\times 25\times 24 }{4\times 3\times 2\times 1}

= \dfrac{421200}{24}

= 17550 solutions

7 0
3 years ago
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