All categories

3 years ago

Subtract (3 + 2i) from (-9 - 8i)

Mathematics

1 answer:

zheka24 [161]3 years ago

4 0

Answer:

$-12-10i$ is the required answer.

Step-by-step explanation:

$\left(-9-8i\right)-\left(3+2i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\\=\left(-9-3\right)+\left(-8-2\right)i\\\\=-12-10i$

Best Regards!

You might be interested in

Explain how you got the answer(:

Natali [406]

Hey there :) I'm pretty sure that your answer is D) ∠S ≅ ∠Y because corresponding angles of similar triangles are congruent.

I think that it is the answer because if you shift your paper around, and look at the angles from different views, you can tell that angles S and Y are congruent, or the same, because of the way that both angles are at the end of the longer sides of both triangles.

So, your answer is D!

~Hope this helped!~

8 0

2 years ago

Read 2 more answers

The solutions to (x + 3)^2- 4=0 are x = -1 and x = -5 True or false

Neko [114]

Answer:

THE ANSWER WOULD BE TRUE MY FRIEND

6 0

2 years ago

Write a quadratic function with zeroes 0 and 8.

Jlenok [28]

Answer:

$x^2-8x=0$

Step-by-step explanation:

the quadratic function should be as follows:

$x^2-8x=0$

Now let's confirm that the zeros of the function are 0 and 8

$x^2-8x=0=x(x-8)=0$

Therefore we can see that if x = 0

$0^2*8*0=0\\0=0$

the equation is fulfilled

And we also have $(x-8)$

for this expresion to be equal to zero:

$x-8=0\\x=8$

thus, if x = 8

$8^2-8*8=0\\64-64=0\\0=0$

the equation is also fulfilled

The zeros of the quadratic function $x^2-8x=0$ are 0 and 8.

3 0

2 years ago

I have so many children but I can’t find them -9(8-6n)

Tatiana [17]

Answer :
-9(8-6n) = 0
-9(2n) = 0
-18n = 0
n = 18

3 0

2 years ago

What is the solution of the equation 3^x=12? Round your answer to the nearest ten-thousandth.

Lady_Fox [76]

Hey!

Okay, so if $f(x)$ equals $g(x)$ , then $In(f(x))$ equals $In(g(x))$ . So, we'll plug in the numbers into this 'equation' we have now.

$In(3^{x} ) = In(12 )$

And now we'll apply this log rule → $log_{a} (x^{b} ) = b * log_{a} (x)$

$In(3^{x} )=xIn(3) \\ xIn(3)=In(12)$

Now we have to solve $In(3^{x} )=xIn(3) \\ xIn(3)=In(12)$ . To do that, we'll divide both sides of the equation by $In(3)$ .

$\frac{xIn(3)}{In3} = \frac{In(12)}{In(3)}$

Now we simplify

$x = \frac{In(12)}{In(3)}$

So, this means the equation $3^{x} =12$ solved is $x = \frac{In(12)}{In(3)}$ or 2.2619.

Hope this helps!

- Lindsey Frazier ♥

6 0

2 years ago

Read 2 more answers