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valkas [14]
2 years ago
11

I've already ruined my brand-new jeans, and i've only had them on for three hour!

SAT
1 answer:
gregori [183]2 years ago
7 0

man that's rough buddy

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How big is the earth?
vitfil [10]

Answer:

3,958.8 mi

Explanation:

5 0
4 years ago
Read 2 more answers
About ​% of the population of a large country is. If two people are randomly​ selected, what is the probability both are ​? what
mezya [45]

Using the binomial distribution, it is found that there is a:

  • 0.0036 = 0.36% probability that both are allergic to pollen.
  • 0.1164 = 11.64% probability that at least one is allergic to pollen.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

Researching the problem on the internet, it is found that:

  • 6% of the population is allergic to pollen, hence p = 0.06.
  • Two people are chosen at random, hence n = 2.

The probability that both are allergic is P(X = 2), hence:

P(X = 2) = 0.06^2 = 0.0036.

0.0036 = 0.36% probability that both are allergic to pollen.

The probability of at least one is:

P(X >= 1) = 1 - P(X = 0) = 1 - 0.94^2 = 1 - 0.8836 = 0.1164.

0.1164 = 11.64% probability that at least one is allergic to pollen.

More can be learned about the binomial distribution at brainly.com/question/24863377

4 0
2 years ago
If A and B are positive integer and A∆B =A(A+2B) , what is the value of 2∆(4∆(1∆B)} ?​
Mariulka [41]

If A ∆ B = A × (A + 2B) = A² + 2AB, then

• 1 ∆ B = 1 + 2B

• 4 ∆ (1 ∆ B) = 4 ∆ (1 + 2B) = 24 + 16B

• 2 ∆ (4 ∆ (1 ∆ B)) = 2 ∆ (24 + 16B) = 100 + 64B

3 0
2 years ago
What right did women in the united states win by 1930? the right to work the right to vote the right to join the military the ri
Tatiana [17]

Answer: B! The right to vote!

Explanation:

just took test 100%

7 0
2 years ago
The distribution of number of hours worked by volunteers last year at a large hospital is approximately normal with mean 80 and
Mazyrski [523]

Explanation:

Using the normal distribution, it is found that the probability that the volunteer selected will receive a certificate of merit given that the  number of hours the volunteer worked is less than 90 is closest to:

B 0.123

In a normal distribution with mean \muμ and standard deviation \sigmaσ , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}Z=σX−μ

It measures how many standard deviations the measure is from the mean.  

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 80, hence \mu = 80μ=80 .

The standard deviation is of 7, hence \sigma = 7σ=7 .

The minimum value is the 80th percentile, which means that it is X_mXm when Z has a p-value of 0.8.

The probability that the volunteer selected will receive a certificate of merit given that the number of hours the volunteer worked is less than 90 is P(X_m < X < 90)P(Xm<X<90) , which is the p-value of Z when X = 90 subtracted by the p-value of Z when X = X_mX=Xm , hence the p-value of Z when X = 90 subtracted by 0.8.

Z = \frac{X - \mu}{\sigma}Z=σX−μ

Z = \frac{90 - 80}{7}Z=790−80

Z = 1.43Z=1.43

Z = 1.43Z=1.43 has a p-value of 0.9236.

0.9236 - 0.8 = 0.1236, hence closest to 0.123, option B.

7 0
3 years ago
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