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1 year ago

5-16 find the general indefinite integral.

1 answer:

6 0

$\displaystyle\int \left( u^6 - 2u^5 - u^3 + \cfrac{2}{7} \right)du\implies \cfrac{u^7}{7}-2\cdot \cfrac{u^6}{6}-\cfrac{u^4}{4}+\cfrac{2}{7}u \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{u^7}{7}- \cfrac{u^6}{3}-\cfrac{u^4}{4}+\cfrac{2u}{7}+C~\hfill$

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Use the BODMAS Rule:

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Answer:

Step-by-step explanation:

The equation is not properly formatted presumably here is the format.

Given

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