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Nastasia [14]
2 years ago
11

5-16 find the general indefinite integral.

Mathematics
1 answer:
aev [14]2 years ago
6 0

\displaystyle\int \left( u^6 - 2u^5 - u^3 + \cfrac{2}{7} \right)du\implies \cfrac{u^7}{7}-2\cdot \cfrac{u^6}{6}-\cfrac{u^4}{4}+\cfrac{2}{7}u \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{u^7}{7}- \cfrac{u^6}{3}-\cfrac{u^4}{4}+\cfrac{2u}{7}+C~\hfill

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3 0
3 years ago
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2 years ago
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artcher [175]

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