Answer:
B
Step-by-step explanation:
Took it
Call the integers 'N' and N+1.. Their sum is 2N+1. Twice their sum is 4N+2. . . Two more than that is 4N+4 and the question says that their product is equal to that. . So write N (N+1) = 4N +4, and then solve that equation to find N. I can tell you right now, by looking at it, that N is 4. You should solve the equation.
Answer:
f+g(2)=10
f-g(4)=-4
F/G(2)= 7/3
(f)(g)(1)=0
Step-by-step explanation:
1. (f+g)=2x+3+x^2-1 2(2)+2=10
2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4
3. f/g= 2x+3/x^2-1 4+3/3= 7/3
4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0
3 is only a Real number because Real Numbers are made like 1,2,3... like counting meanwhile the other two, complex numbers are a real number +b(i) and imaginary numbers are anything with i. Hope this helps!
