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2 years ago

The following equations estimate the calories burned when exercising (source):

Computers and Technology

1 answer:

riadik2000 [5.3K]2 years ago

8 0

Answer:

# Women: Calories = ((Age x 0.074) - (Weight x 0.05741) + (Heart Rate x 0.4472) - 20.4022) x Time / 4.184

#Men: Calories = ((Age x 0.2017) + (Weight x 0.09036) + (Heart Rate x 0.6309) - 55.0969) x Time / 4.184

#main function to gets input for age, weight, hear rate and time and print Women and Man calorie burnt

def main():

#get user input for age, weight, hear rate and time

age = int(input("Enter your age:"))

weight = int(input("Enter your weight:"))

heartRate = int(input("Enter your heart rate:"))

time = int(input("Enter your time:"))

#calculate calories for women and men

caloriesWomen = ((age * 0.074) - (weight * 0.05741) + (heartRate * 0.4472) - 20.4022) * time / 4.184

caloriesMen = ((age * 0.2017) + (weight * 0.09036) + (heartRate * 0.6309) - 55.0969) * time / 4.184

#print calories for women and men

print("Women: %.2f calories"%caloriesWomen)

print("Men: %.2f calories"%caloriesMen)

#calling main function

main()

Explanation:

1) Above is your updated program.

2) Please copy it in python file and run

3) Below is the test output for this program

Enter your age:49

Enter your weight:155

Enter your heart rate:148

Enter your time:60

Women: 580.94 calories

Men: 891.47 calories

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3 years ago

Write a function that accepts a pointer to a C-string as an argument and returns the number of words contained in the string. Fo

Anon25 [30]

Answer:

To preserve the original format of the answer, I've added it as an attachment

Explanation:

This line defines the function

int countWords(const char ptr){

This line initializes number of words to 0

int words = 0;

The following iteration is repeated until the last character in the argument is reached

while(*(ptr) != \0){

This checks if current character is blank

if(*ptr== ){

If yes, then it increments number of words by 1

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}

This moves the pointer to the next character

ptr++;

}

This returns the number of words in the argument

return words+1;

}

The main begins here

int main() {

This declares user input as a character of 200 length

char userinput[200];

This prompts user for input

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This gets user input

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This passes the c-string to the function and also prints the number of words

cout << There are << countWords(userinput)<< words;

Download cpp

4 0

3 years ago

Your program will read a word (or a whole line) from the user. It will then count the number of vowels in the word (or line) and

Softa [21]

Answer:

Following are the program in the Python Programming Language.

def vowel(): #define function

print("Enter END to Break") #print message

while(True): #set while loop

word=input("Enter words: ") #get input from the user

count=0 #set count to 0

if(word=="END"): #set if condition

break #terminate the loop

else:

for i in range(len(word)): #set the for loop

c=word[i] #initialize in c

if(c=='a'or c=='e' or c=='i'or c=='o'or c=='u'or c=='A'or c=='E'or c=='I'or c=='O'or c=='U'):

count+=1 #increament in count by 1

print("The word " , word , " contains " , count, end=" ")#print message

if(count==1):#check condition

print("vowel.")

else:

print("vowels")

#call the function

vowel()

Output:

Enter END to Break

Enter words: Vowel

The word Vowel contains 2 vowels

Enter words: END

Explanation:

Here, we define a function "vowel()" inside it.

Print message for the user.
Set the while loop and pass condition is True then, get input from the user in the variable "word" then, set variable "count" and initialize to 0.
Set if condition to check if the user input "END" then, the loop will terminate.
Otherwise, set for loop which continues from the length of the word.
Then, we set if statement which checks the vowel in the word, then increment in count by 1.
Print the message in the following format which is mentioned in the question.
Then, set if-else statement for check count is equal to 1 then print "vowel." Otherwise, it prints "vowels."

Finally, we call the following function "vowel()".

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