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irga5000 [103]
3 years ago
9

What is the volume of a right pyramid whose base is a square with a side 6m long and whose altitude is equal to the base side? A

. 72 m3 B. 216 m3 C. 36 m3 D. 108 m3
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
The 4-dimensional volume<span> of a polyhedral </span>pyramid<span> is 1/4 of the </span>volume<span> of the base polyhedron times its perpendicular height, compared to the area of a triangle being 1/2 the length of the base times the height and the </span>volume<span> of a </span>pyramid<span> being 1/3 the area of the base times the height.</span>
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A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par
ElenaW [278]

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

-7x+3y=-21.5  

Convert it to the general form given below:

\rm y=mx+c

\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x or

\rm y = \frac{7}{3}x-\frac{21.5}{3}

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For the slope(m') of the PQ line:

\rm m'=-\frac{1}{m}    ( because AB and PQ are perpendicular to each other)

\rm m' = -\frac{3}{7}

We know the:

\rm (y-y')=m'(x-x')

Where (x', y') = (7, 6), we get:

\rm (y-6)=-\frac{3}{7} (x-7)

\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63

\rm -1.5x-3.5y=-31.5   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

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Step-by-step explanation:

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