Question

a circle has its center at (−2, 5) and a radius of 4 units. what is the equation of the circle? (1 point) (x 2)2 (y − 5)2 = 16 (x 2)2 (y 5)2 = 16 (x 2)2 (y − 5)2 = 4 (x − 2)2 (y 5)2 = 4

Answer 1

( x + 2 )^2 + ( y - 5 )^2 = 16

the answer is the first one

Answer 2

Answer:

$(x+2)^2+(y-5)^2=16$

Step-by-step explanation:

We have been given that a circle has its center at (−2, 5) and a radius of 4 units. We are asked to write the equation of the circle.

We know that standard equation of circle is in form $(x-h)^2+(y-k)^2=r^2$, where, (h,k) represents vertex of circle and r represents radius of circle.

Upon substituting coordinates of vertex $(-2,5)$ and $r=4$ in above equation, we will get:

$(x-(-2))^2+(y-5)^2=4^2$

$(x+2)^2+(y-5)^2=16$

Therefore, the equation of our given circle would be $(x+2)^2+(y-5)^2=16$.