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Ivenika [448]
3 years ago
15

a circle has its center at (−2, 5) and a radius of 4 units. what is the equation of the circle? (1 point) (x 2)2 (y − 5)2 = 16 (

x 2)2 (y 5)2 = 16 (x 2)2 (y − 5)2 = 4 (x − 2)2 (y 5)2 = 4
Mathematics
2 answers:
zalisa [80]3 years ago
6 0
( x + 2 )^2 + ( y - 5 )^2 = 16

the answer is the first one
n200080 [17]3 years ago
3 0

Answer:

(x+2)^2+(y-5)^2=16

Step-by-step explanation:

We have been given that a circle has its center at (−2, 5) and a radius of 4 units. We are asked to write the equation of the circle.

We know that standard equation of circle is in form (x-h)^2+(y-k)^2=r^2, where, (h,k) represents vertex of circle and r represents radius of circle.

Upon substituting coordinates of vertex (-2,5) and r=4 in above equation, we will get:

(x-(-2))^2+(y-5)^2=4^2

(x+2)^2+(y-5)^2=16

Therefore, the equation of our given circle would be (x+2)^2+(y-5)^2=16.

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