Answer:
45 3/10 miles per hour
Step-by-step explanation:
Distance travelled by the car = 30 1/5 miles
Time taken = 2/3 of an hour
Average speed = distance travelled / time taken
= 30 1/5 miles ÷ 2/3 of an hour
= 151/5 ÷ 2/3
= 151/5 × 3/2
= (151 * 3) / (5 * 2)
= 453 / 10
= 45 3/10 miles per hour
Average speed = 45 3/10 miles per hour
Answer:
16
Step-by-step explanation:
We can use the Pythagorean theorem to find the height
a^2 + b^2 = c^2 with a and b legs and c the hypotenuse
The triangle is a right triangle with legs GH and FG and hypotenuse FH
FG^2 + GH^2 = FH^2
FG ^2 + 12^2 = 20^2
FG^2 +144 = 400
Subtract 144 from each side
FG^2 +144-144 = 400-144
FG^2 =256
Take the square root of each side
sqrt(FG^2) =sqrt(256)
FG = 16
The answer would be 61. First, if you are trying to figure out the pattern. You must subtract the
second number with the first then fourth number with the fifth and so
on, you get.
73 minus 66 equals 7.
21 minus 13 equals 8.
XX minus 52 equals x.
20 minus 10 equals 10.
Basing on the pattern of the set of numbers, x will equal 9, To get this you must do 52 and 9 which will equal 61.
Answer:
6 hope you get the point.
Answer:
Given:
In Rhombus QRST, diagonals QS and RT intersect at W and U∈QR and point V∈RT such that UV⊥QR. (shown in below diagram)
To prove: QW•UR =WT•UV
Proof:
In a rhombus diagonals bisect perpendicularly,
Thus, in QRST
QW≅WS, WR ≅ WT and m∠QWR=m∠QWT=m∠RWS=m∠TWS=90°.
In triangles QWR and UVR,
(Right angles)
(Common angles)
By AA similarity postulate,
The corresponding sides in similar triangles are in same proportion,
(∵ WR ≅ WT )
Hence, proved.
