All categories

3 years ago

The empire that was ruling when Jesus Christ was born was the this is bible not SAT

2 answers:

4 0

Um your best answer that i know will be in sat so idk how to explain this to you (p.s i am filming a youtube vid check it out Hailey Tarlton go subscribe

zheka24 [161]3 years ago

3 0

In what part of the world specifically? There were many thriving in different parts of the world at that time.

You might be interested in

And IT So, what was it?

larisa86 [58]

Answer:

waka waka wa e e

Explanation:

queen shakira

3 0

3 years ago

The area of a rectangle whose width is 5 less than its length.

PSYCHO15rus [73]

Answer:

Explanation:

We know the area of the rectangle is length * width

We also know width = length - 5

Thus area is $length * (length - 5) = (length)^{2} - 5* length$

5 0

2 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

The proportion of Good TV set is 0.67
The number of ways of selecting 5 from 6 TV sets is 6
The number of ways of selecting 4 from 6 TV sets is 15

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

(a) Proportion that are good

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

(b) Ways to select 5 samples (without replacement)

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

(c) All possible sample space of 4

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

(d) The sampling distribution

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

3 0

3 years ago

The area between z= -2.31 and z= 0.47

siniylev [52]

Answer:

0.67038

Explanation:

One z-value is negative and the other is positive.

This means we are looking for area between the two given z-values on opposite sides of the mean.

From z-table attached, the area at z = -2.31 is 0.98956

Also, from the second z-table attached, the area at z = 0.47 is 0.68082

But since we are looking for the area between both z-scores, we will now have;

P(-2.31 < x < 0.47) = (0.98956 + 0.68082) - 1

P(-2.31 < x < 0.47) = 0.67038

5 0

2 years ago

Why is it important to develop social competence among young children? Please help me

Margaret [11]

Answer:

It’s important to develop social competence among young children because social competence allows children to interact and talk with their peers in a variety of ways. It’s also important to develop social competence among young children to maintain positive relationships with their peers and other adults.

4 0

3 years ago