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2 years ago

Point c partitions line segment AB in the ratio 1:3. What is the y-coordinate of c.

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

8 0

The y-coordinate of c is -4 if the Point c partitions line segment AB in the ratio of 1:3.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have two points:

A(-4, -7), and B(12, 5)

Let's assume A(x1, y1) and B(x2, y2)

The ratio is 1:3 = m:n

Let's assume the y-coordinate is a

From the section formula:

$\rm a = \dfrac{my_2+ny_1}{m+n}$

$\rm a = \dfrac{1\times5+3\times(-7)}{1+3}$

a = -4

Thus, the y-coordinate of c is -4 if the Point c partitions line segment AB in the ratio of 1:3.

Learn more about the straight line here:

brainly.com/question/3493733

#SPJ1

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3 years ago

Which of the followingis multiplicative of -a? (-1/a a 1 1/a)

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Given:

The given value is $-a$ .

To find:

The multiplicative inverse of $-a$ .

Solution:

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3 years ago

What are the values of a and b

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3 years ago

A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately

Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

$z=\frac{\bar x-\mu}{\sigma/\sqrt N}$

where

$\bar x=mean\; of\;the \;sample$

$\mu=mean\; established\; in\; H_0$

$\sigma=standard \; deviation$

N = size of the sample.

So,

$z=\frac{185-175}{20/\sqrt {10}}=1.5811$

$\boxed {z=1.5811}$

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is

$\boxed {p=0.057}$

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

Step 1

Compute $\bar x_{critical}$