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Tcecarenko [31]
3 years ago
8

Find the first six terms of the sequence. a1 = -8, an = 5 • an-1

Mathematics
1 answer:
lozanna [386]3 years ago
5 0
a_1 = -8\\
a_n = 5 \cdot a_{n-1 }\\\\
a_2=5\cdot(-8)=-40\\
a_3=5\cdot(-40)=-200\\
a_4=5\cdot(-200)=-1000\\
a_5=5\cdot(-1000)=-5000\\
a_6=5\cdot(-5000)=-25000
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Plz help!! Given: DE is a midsegment of ABC. Show all work.
topjm [15]

Answer:

AC=14

X=10

Y=1

Hoped this helped!

Step-by-step explanation:

DE is half of BC, therefore x=10. AE and EC have to be the same length, which is 7. SO, y=1 and x is 10.

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2 years ago
Nguyen played a game in which he could either lose or gain points each round. at the end of 7 rounds, he had -8 points. After on
Sergeeva-Olga [200]

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Step-by-step explanation:

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2 years ago
21. Brian wants to purchase a piece of fabric
ella [17]

Brian should purchase Choice C of fabric

<em><u>Solution:</u></em>

Given that Brian wants to purchase a piece of fabric  that is between 49 and 53 inches long

So piece of fabric should be between: 49 and 53 inches

  • Choice A is 4\frac{3}{4} feet long

Let us convert feet to inches

4\frac{3}{4} feet = \frac{4 \times 4 + 3}{4} = \frac{19}{4} feet

Now convert to inches

We know that,

1 feet = 12 inches

\frac{19}{4} feet = \frac{19}{4} \times 12 = 57 inches

But this choice is greater than given condition that piece of fabric should be between: 49 and 53 inches

So this is not correct

  • Choice  B is 4\frac{1}{2} feet long

4\frac{1}{2} feet = \frac{2 \times 4 + 1}{2} = \frac{9}{2} feet

Now convert to inches

\frac{9}{2} feet = \frac{9}{2} \times 12 inches = 54 inches

But this choice is greater than given condition that piece of fabric should be between: 49 and 53 inches

So this is not correct

  • Choice C is 4\frac{1}{3} feet  long

4\frac{1}{3} feet = \frac{3 \times 4 + 1}{3} = \frac{13}{3} feet

Now convert to inches

\frac{13}{3} feet = \frac{13}{3} \times 12 inches = 52 inches

So this 52 inches lies between 49 and 53 inches

So Brian should purchase Choice C of fabric

8 0
3 years ago
3.<br> If r=9.b=5, and g=-6, what does (r +b-8)(b + g) equal?
VLD [36.1K]

Answer:

-6

Step-by-step explanation:

r = 9, b = 5, g = -6

Plug these values into (r + b - 8)(b + g)

[(9) + (5) - 8]*[(5) + (-6)]

Combine like terms in the brackets

[6]*[-1]

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8 0
3 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

4 0
3 years ago
Read 2 more answers
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