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vesna_86 [32]
2 years ago
14

Mr. Washington drills a water well. Ground conditions cause an increase of 5% to the cost per meter, c. In addition, the cost of

equipment is $1,400. He calculates the cost of his well using the expression 1, 400 + 1.05c . What other expression could he have used?

Mathematics
1 answer:
goblinko [34]2 years ago
3 0
Answer: C
Explanation:
c and 0.05c are like terms, so they can be simplified to be 1.05c. Therefore, c + 0.05c + 1400 = 1.05c + 1400.
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3 years ago
Please answer asap will give brainiest
lubasha [3.4K]

Answer:

79% - almost 4 times out of 5.

The key to this is realizing that the number of games will not always be 5.

If A wins in a sweep - you have 2/3*(2/3)*2/3 percent chance of that happening - 8/27, or 29.63%

If A wins in 4, now we have 2/3*(2/3)*2/3*(1/3)*3 - the 1/3 is the chance that B wins a game. Note - there are only 3 ways B can win a game, not 4. B cannot win Game 4 because Game 4 would not be played in case of a sweep. That is why you cannot use a straight Pascal’s triangle to get your coefficients - the 1–4–6–4–1 is not possible if B cannot win Game 4. Anyway, the math is the same as the above, a 29.63% chance of A winning in 4.

For a 5 game set, A could lose 2 games in 6 possible ways (lose 1&2, 1&3, 1&4, 2&3, 2&4 or 3&4). Again, A cannot lose Game 5 - it would not be played once A wins 3 games. So the odds become 2/3*(2/3)*2/3*(1/3)*(1/3)*6, or 19.75%.

Add them up and you get 79.01%

Step-by-step explanation:

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6 0
3 years ago
A fence is to be built to enclose a rectangular area of 800 square feet. The fence along three sides is to be made of material t
myrzilka [38]

Answer:

dc/dx = 0 when x = 20. hence fence is 20×40

Step-by-step explanation:

Given data:

Rectangular Area = 800 ft^2

three side material cost = $5 per ft

fourth side material cost is $15 per ft

let expensive side is x and other dimension assume to be y

Then cost is c

c = 5(x+ 2y) + 15 x

xy = 800, so y = 800/x

c =5(x+ 1600/x^2) + 15x

for minimum when dc/dx = 0

\frac{dc}{dx} = 5(1-\frac{1600}{x^2}) + 15 = 0

5(1-\frac{1600}{x^2}) +  15 = 0

(1-\frac{1600}{x^2}) + 3 = 0

(1-\frac{1600}{x^2}) = - 3

x^2 - 1600 = -3x^2

4x^2 - 1600 = 0

(2x-40)(2x+40) = 0

x = 20

dc/dx = 0 when x = 20. hence fence is 20×40

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LUCKY_DIMON [66]

Answer:

(2,-1.5)

Step-by-step explanation:

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3 years ago
Does 4(x−8)+12=2(2x−9) have one solution, no solution, or infinitely many solutions? <br><br> ??
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Answer:

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Step-by-step explanation:

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