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saveliy_v [14]
3 years ago
11

Desiree works 28 hours per week. She has a monthly income of $120 from investments. Desiree also plays in a band one night a wee

k making $200. She has a total annual income of $49,696. Desiree wants to ask her boss for a raise so that next year she can have a total income of $51,880. Assuming the other incomes remain the same, how much of an hourly raise will Desiree need? a. $1.25 b. $1.50 c. $1.75 d. $2.00
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440

she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400

her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856

so, she makes from her job, $37856 annually

now, she only works 28 hours weekly, how much is that yearly?   well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that

37856 ÷ ( 28 * 52)   well, it ends up as 26

so, her hourly payrate is $26 per hour

now, she wants to ask for a raise, to make 51880 annually

well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount

51880 - 49696 = 2184

ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually?  well 2184 ÷ ( 28 * 52)
aalyn [17]3 years ago
6 0
The answer is B. $1.50
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the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

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Let x be the number of rectangular containers and y the number of cylindrical containers.

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We have that the maximum volume of the truck V = 100x + 200y.

Also, the maximum weight of the truck is W = 200x + 100y

Since V = 4200 ft.³  and W = 4800 pounds,

100x + 200y = 4200 and 200x + 100y = 4800

x + 2y = 42 (1) and 2x + y = 48 (2)

Multiplying (1) by 2 and (2) by 1, we have

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Subtracting (4) from (3), we have

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y = 12

Substituting y into (1), we have

x + 2y = 42

x + 2(12) = 42

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x = 42 - 24

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Also, since the shipping company charges $60 for a rectangular container and $55 for a cylindrical container, the income, P = 60x + 55y

Since x = 18 and y = 12, the maximum income is P = 60x + 55y

= 60(18) + 55(12)  

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So, the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Learn more about maximum income here:

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Step-by-step explanation:

For this case we know the following info:

Total waste generated for a certain country in 2005 : 4.033x10^9 pounds

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