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Alex787 [66]
3 years ago
15

Use the vertical line test to determine if the graph below represents a function. If it is not a function, tell where the vertic

al line test fails.

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

1: Function    2: Function   3: Not a Function

Step-by-step explanation:

there-

Step2247 [10]3 years ago
3 0

Answer:

see attached

Step-by-step explanation:

The vertical line test for a function passes when, if you draw a vertical line which intersects the graph, the line intersects the graph at ONLY ONE point.

It is quite clear that for all positive values of X, any vertical line will intersect the graph at 2 points, thereby failing the vertical line test for a function.

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3 years ago
How do you find the height of a triangle?
Dmitrij [34]
Answers:  height, "h", of a triangle:    <span> h = 2A /  (b₁ + b₂) .
___________________________________________________ </span>
Explanation:
__________________________________________________
The area of a triangle, "A", is equal to (1/2) * (b₁ + b₂) * h ; 
                                    or:  A = (1/2) * (b₁ + b₂) * h
                                    or: write as:  A =  [(b₁ + b₂) * h] / 2 ;
          ___________________________________________
                                     in which:  A = area of the triangle; 
                                                       b₁ = length of one of the bases
                                                                 of the triangle ("base 1");
                                                       b₂ = length of the other base
                                                                 of the triangle ("base 2");
                                                       h = height of the triangle;
____________________________________________________
To find the height of the triangle, we rearrange the formula to solve for "h" (height); assuming that all the units are the same (e.g. feet, centimeters); if no "units" are given, then the assumption is that the units are all the same.
We can use the term "units" if desired, in such cases; in which the area, "A" is measured in "square units"; or "units²",
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So, given our formula for the "Area, "A"; of a triangle:
_________________________________________________
 A =  [(b₁ + b₂) * h] / 2 ; we solve for "h" in terms of the other values; by isolating "h" (height) on one side of the equation.
     If we knew the other values; we plug in the those other values.
______________________________________________
  Given:   A =  [(b₁ + b₂) * h] / 2 ;

Multiply EACH side of the equation by "2" ;
_________________________________________
            2*A = {  [(b₁ + b₂) * h] / 2 } * 2 ;
_________________________________________
to get:
_________________________________________
           2A = (b₁ + b₂) * h ;
_____________________________________________________
           Now, divide EACH side of the equation by:  "(b₁ + b₂)" ;  to isolate "h"
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_____________________________________
            2A /  (b₁ + b₂) = [ (b₁ + b₂) * h ] / (b₁ + b₂);
______________________________________
to get:
_______________________________________________
           2A /  (b₁ + b₂)  =  h ;  ↔<span>  h = 2A /  (b₁ + b₂)  .
__________________________________________________</span>
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