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Svetllana [295]
2 years ago
14

To make sure that a given parallelogram is a rectangle, at least hon many of

Mathematics
1 answer:
zmey [24]2 years ago
8 0

Answer:

D. One

Step-by-step explanation:

     A parallelogram will have two sets of equal sides. Since we have that fact, all we need to know are the angles.

     A quadrilateral will have a total of 360° in its angles. If only one angle is equal to 90°, then we can do <u>the math</u> to figure out that all the others must be 90° as well. A rectangle is a parallelogram with the opposite sides being parallel and all the angles being 90°. This then answers the question.

     "<u>The Math</u>"

-> Keep in mind there will be four angles

-> Once we subtract the first angle of 90°, we will have three angles left. Hence why we divide by 3.

360° - 90° = 270°

270° / 3 = 90° ✓

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URGENT!!!!! 25 POINTS!! Find the perimeter of the triangle with coordinates A(2,7), B(10,5), and C(10,1) Round to the nearest te
nikdorinn [45]

Answer:

Step-by-step explanation:

Hello!

First, calm down. Now, think. Plot those points on a coordinate graph! I don't have coordinate graph at hand right now, but if you plot them, you should get the answer. Remember, if there are diagonal lines, then use the pythagorean theorem!

7 0
3 years ago
Which of the following is equivalent to the polynomial given below?
Marizza181 [45]

Answer:

(x+(3+\sqrt{11}i)) (x+(3-\sqrt{11}i))

Step-by-step explanation:

The first step to this problem is to look at the key features of the initial expression given to us. Namely, the middle term.

Notice that it is just +6x. This indicates that the square root terms cancel out, meaning that their signs need to be opposite, but the threes need to have the same, positive sign. This indicates that our answer is option C, but you should always double check by multiplying the expression out to confirm. Here are the steps:

(x+(3+\sqrt{11}i)) (x+(3-\sqrt{11}i))

x^{2} +(3+\sqrt{11}i)x+(3-\sqrt{11}i)x+(3+\sqrt{11}i)(3-\sqrt{11}i)x^{2}+3x+\sqrt{11}ix+3x-\sqrt{11}ix+9+3\sqrt{11}i-3\sqrt{11}i-(\sqrt{11})^{2}(i^{2})x^{2}+6x+9-(11)(-1)

x^{2}+6x+9+11

x^{2}+6x+20

Therefore as we suspected, the answer is C.

3 0
3 years ago
Four points are always coplanar if they:
Vera_Pavlovna [14]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A square has a side length of 6. A rectangle has a length of 5x + 12 in a width of 5x. Find the sum of the areas of square and r
nata0808 [166]

Answer:

D) (5x + 6)(5x + 6)

Step-by-step explanation:

area of square = 6 x 6 = 36

area of rectangle = 5x(5x + 12) = 25x² + 60x

total together = 25x² + 60x + 36

factored:

(5x + 6)(5x + 6)

5 0
3 years ago
Plz help. Attachment below
Vinvika [58]

Answer:

The value of k is 1.

Step-by-step explanation:

You have to apply Indices Law :

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

For this question :

{( \frac{4}{5} )}^{2}  \times  {( \frac{4}{5} )}^{5}  =  {( \frac{4}{5} )}^{6k + 1}

{( \frac{4}{5}) }^{2 + 5}  =  {( \frac{4}{5}) }^{6k + 1}

by \: comparison

2 + 5 = 6k + 1

7 = 6k + 1

7 - 1 = 6k

6k = 6

k = 6 \div 6

k = 1

7 0
4 years ago
Read 2 more answers
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