B. The levels of classification increased. Previously there were only 2 domains of life, Bacteria and Eukarya, but an additional domain and Kingdom were added when the distinction of Archaea was observed.
Answer: Four pulmonary veins.
Explanation: Oxygen and nutrient rich blood will flow from the lungs back into this part called the left atrium (Or as some will call it, the left upper chamber in the heart). From there, it goes through four pulmonary veins.
Hope I could help! :)
Answer:
Nutrient pollution is the process where too many nutrients, mainly nitrogen and phosphorus, are added to bodies of water and can act like fertilizer, causing excessive growth of algae. Nutrients can run off of land in urban areas where lawn and garden fertilizers are used
Explanation:
Answer: 1. Sea urchins and sea otters
2. They are prey for carnivores.
3. Sea otters, star fish
Explanation:
Sea urchins and sea otters are carnivores as they eat on the flesh of starfish and sea urchins respectively.
Starfish feed on the kelp forests which are the producers in the food chain and the starfish is the primary consumer and prey for sea urchins. So, starfish and kelp forests are the prey in the marine ecosystem.
Keystone species is the one which controls the population of other inferior species in an ecosystem. Here, sea otters consume sea urchins so the population of sea urchins remained in control Starfish controls the population of kelp forest.
CH2O5 +603-6CO2 + 6H2O + energy isn't the evidence of conservation of mass in cellular respiration.
Option B
<h3><u>Explanation:</u></h3>
Law of conservation of mass states that mass can neither be created nor be destroyed. And this law holds good for all sorts of chemical reactions except the nuclear reactions.
In case of cellular respiration, one molecule of glucose reacts with 6 molecules of oxygen to produce 6 molecules of carbon dioxide and 6 molecules of water and energy. Now this energy that is produced isn't produced in expense of mass, but in expense of chemical bonds that are present in glucose molecules.
Also if we calculate the number of atoms on each side of the reaction, the number of atoms remain same as well as number of atoms of individual elements also remain same.
