Slope intercept form
y=mx+b
m=slope
b=yintercept
slope for the line passing through the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(2,-2) and (2,-3)
slope=(-3-(-2))/(2-2)=(-1)/0=undefined
y=undefinedx
this means that the equation is x=something
we see
(x,y)
(2,-2)
(2,-3)
x=2 is the equation
we cannot write it in slope intercept form
Answer:
The terminal point is (1, 0) ⇒ D
Step-by-step explanation:
In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis.
- The terminal point on the positive part of the x-axis is (1, 0),which means Ф = 0° or 360° and cosФ = 1, sinФ = 0
- The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
- The terminal point on the negative part of the x-axis is (-1, 0),which means Ф = 180° and cosФ = -1, sinФ = 0
- The terminal point on the negative part of the y-axis is (0, -1),which means Ф = 270° and cosФ = 0, sinФ = -1
In a unit circle
∵ Ф = 2π radians
∵ 2π radians = 360°
→ By using the 1st rule above
∴ The terminal point is (1, 0)
Answer:
"g(x) = log₂(x) + 2" is the closest graph to what g(x) would be, slightly above f(x) and curving up.
