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nignag [31]
4 years ago
15

Write the slopes intercept form of the equation of the line through the given points.

Mathematics
1 answer:
Anika [276]4 years ago
8 0
Slope intercept form
y=mx+b
m=slope
b=yintercept

slope for the line passing through the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

given
(2,-2) and (2,-3)
slope=(-3-(-2))/(2-2)=(-1)/0=undefined

y=undefinedx
this means that the equation is x=something
we see
(x,y)
(2,-2)
(2,-3)
x=2 is the equation
we cannot write it in slope intercept form
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Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or
NARA [144]

Answer:

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

Step-by-step explanation:

The function is:

f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y

The partial derivatives of the function are included below:

\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y

\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)

\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x

\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)

Local minima, local maxima and saddle points are determined by equalizing  both partial derivatives to zero.

y \cdot (8\cdot y -16\cdot x + 9) = 0

x \cdot (16\cdot y - 8\cdot x + 9) = 0

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

x\cdot (-8\cdot x + 9) = 0

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

y\cdot (8\cdot y+9) = 0

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}

The second derivatives of the function are:

\frac{\partial^{2} f}{\partial x^{2}} = 0

\frac{\partial^{2} f}{\partial y^{2}} = 0

\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9

Then, the expression is simplified to this and each point is tested:

H = -16\cdot y +16\cdot x -9

S1: (0,0)

H = -9 (Saddle Point)

S2: (3/8,-3/8)

H = 3 (Local maximum or minimum)

S3: (9/8, 0)

H = 9 (Local maximum or minimum)

S4: (0, - 9/8)

H = 9 (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64} (Local minimum)

S3: (9/8, 0)

f(\frac{9}{8},0) = 0 (Local maximum)

S4: (0, - 9/8)

f(0,-\frac{9}{8} ) = 0 (Local maximum)

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

4 0
3 years ago
What is the Product of x-3 and x-9​
Serggg [28]

Answer:

x^2-12x+27

Step-by-step explanation:

(x-3)(x-9)=x^2-3x-9x+27=x^2-12x+27

4 0
3 years ago
How do I find 3/4 as a fraction
antiseptic1488 [7]
Divide 3 by for to get 0.75 but that is a fraction
5 0
3 years ago
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The lengths of three sides of a triangle are 2x, 3x-4, and x+4. Find a value of x that makes the triangle equilateral
Furkat [3]
Espero que no me jusgas por esto que estoy escribiendo
4 0
3 years ago
a small bar of gold is a rectangular prism that measures 40 millimeters by 25 millimeters by 2 millimeters. one cubic millimeter
guajiro [1.7K]
Step One 
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V= l*w*h
l =40 mm
w = 25 mm
h = 2 mm
V = 40*35 * 2
V = 2800 mm^3

Step Two
Find the weight
1  mm^3 = 0.0005
2800 mm^3 = x   <<<<< answer 1

\frac{1}{2800} =  \frac{0.0005}{x}   Cross multiply.

1x = 2800 * 0.0005
x = 1.4 ounces.  <<<<< answer 2


9 0
4 years ago
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