Answer:
y = - 4x + 3
Step-by-step explanation:
The perpendicular bisector is positioned at the midpoint of AB at right angles.
We require to find the midpoint and slope m of AB
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = A(3, 8) and (x₂, y₂ ) = B(- 5, 6)
m = 
= 
= 
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= - 4
mid point = [0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]
Using the coordinates of A and B, then
midpoint AB = [0.5(3 - 5), 0.5(8 + 6) ] = (- 1, 7 )
Equation of perpendicular in slope- intercept form
y = mx + c ( m is the slope and c the y- intercept )
with m = - 4
y = - 4x + c ← is the partial equation
To find c substitute (- 1, 7) into the partial equation
Using (- 1, 7), then
7 = 4 + c ⇒ c = 7 - 4 = 3
y = - 4x + 3 ← equation of perpendicular bisector
I can help you with 11 so its 588 because I know that 600 divide by 12 equals 50 so they said they want less then 600 so I tried 49 times 12 equals 588
In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:
‹1, -1, 1› × ‹0, 1, 1›
You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.
So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...
In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0
That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:
a - b + c = 0
b + c = 0
This is two equations, three unknowns, so you can solve it with one free parameter:
b = -c
a = c - b = -2c
The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›
The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:
|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6
Then we divide that vector by its magnitude to yield one solution:
‹ -2/√6 , -1/√6 , 1/√6 ›
And take the negative for the other:
‹ 2/√6 , 1/√6 , -1/√6 ›
Answer:
second option
Step-by-step explanation:
The answer is D. It can't be considered a funtion unless each X value only has 1 Y value corresponding to it. In this problem, you see the X value 3 paired with -1 and 1.
