Question

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

Answer 1

Answer:

6

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

$\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}$

And we need to find out the value of A , when

• a = 3
• b = 4
• c = 5

So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)}$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}$

$\sf\red{\longrightarrow}A = 3*2$

$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$