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Sphinxa [80]
2 years ago
10

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

Mathematics
1 answer:
kramer2 years ago
7 0

Answer:

6

Step-by-step explanation:

Here it's given that ,

\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}

Also ,

\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}

And we need to find out the value of A , when

  • a = 3
  • b = 4
  • c = 5

So , on substituting the respective values to find s we have ,

\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}

Now let's find out A as ,

\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\

\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\

\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\

\sf\red{\longrightarrow}A = 3*2\\

\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}

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Step-by-step explanation:

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