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Lemur [1.5K]
3 years ago
8

An airline allows each passenger 33 kilograms of luggage. Carl has to lower the weight of his suitcase by 25% to stay within the

limit. How much did the suitcase originally weigh?
Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:

44 kg.

Step-by-step explanation:

The weight limit of the luggage = 33 kg

Let the original weight of the suitcase = x kg

Now, it has been given that Carl has to lower the weight of his suitcase by 25% to stay within the limit.

It means that if we decrease the original weight of the suitcase by 25% then it should be equal to 33 kg.

Thus, we have the equation

x-0.25x=33

Solve the equation

0.75x=33\\\\x=\frac{33}{0.75}\\\\x=44

Therefore, the original weight of the suitcase was 44 kg.

damaskus [11]3 years ago
5 0
1- 0.25= 0.75 (multiplier)

33÷0.75=44

The suitcase originally weighed 44kg

Hope this helps!
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2/3 is exactly the same as 8/12
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Read 2 more answers
Simplify this expression
pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

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3 years ago
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4 0
3 years ago
e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv
Naddika [18.5K]

Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

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