Answer:
Step-by-step explanation:
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Firstly we will make PMF
For X=0, P=(4/5)^3=64/125
For X=1, P=C(3,1)*(1/5)*(4/5)^2=3*16/125=48/125
For X=2, P=C(3,2)*(1/5)^2*(4/5)=3*4/125=12/125
For X=3, P=C(3,3)*(1/5)^3=1/125
So,
E[X^2]=1*48/125+2^2*(12/125)+3^2/125=0.84
E[X]=48/125+12/125*2+1/125*3=0.6
So,
E[X]^2=0.36

the va's are where x is undefined, or where the denomenator is zero
first simplify if applicable
cannot simplify
set denom to zero
2x-5=0
2x=5
x=2.5
the vertical assemtote is vertical so it is x=2.5 or 5/2
the VA is x=5/2
As we know
area of triangle = 1/2 *height*base
32=1/2*8*base
32=4*base
8 =base
Answer:
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