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NARA [144]
1 year ago
11

How does the number of jobs in internet media compare to the number of jobs in tv broadcasting and print media?

Computers and Technology
1 answer:
sashaice [31]1 year ago
5 0

The number of jobs in internet media is a lot when compare to the number of jobs in tv broadcasting and print media as people can now work remotely from home.

<h3>What is the role of media in entertainment?</h3>

The function of mass media in entertainment is mostly to get the people inform and also entertained.

Note that The number of jobs in internet media is increasing daily as people are creating a lot of content when compare to the number of jobs in tv broadcasting and print media as people can now work remotely from home.

Learn more about internet media from

brainly.com/question/13467876

#SPJ1

You might be interested in
Which of the following is not a mobile means of connecting devices to networks?
ElenaW [278]

Answer:

USB cables.

Explanation:

Think of what would happen if you started walking to a friend's house that is 3 houses away from yours. You have a cell and there are no others that you can see. Your friend calls you.

Could you hear what he says with a blue tooth earphone? Likely.

If you are connected by a wifi device. Again likely.

What about a broad band. That would be possible too.

So what about a USB cable. Now there's a problem. The cable would have to be at least 75 feet long (city plots are usually somewhere in the neighborhood of 25 feet wide). You would need an awfully long cable. And that's only 3 houses away.

6 0
3 years ago
Define a class called TreeNode containing three data fields: element, left and right. The element is a generic type. Create cons
m_a_m_a [10]

Answer:

See explaination

Explanation:

// Class for BinarySearchTreeNode

class TreeNode

{

// To store key value

public int key;

// To point to left child

public TreeNode left;

// To point to right child

public TreeNode right;

// Default constructor to initialize instance variables

public TreeNode(int key)

{

this.key = key;

left = null;

right = null;

key = 0;

}// End of default constructor

}// End of class

// Defines a class to crate binary tree

class BinaryTree

{

// Creates root node

TreeNode root;

int numberElement;

// Default constructor to initialize root

public BinaryTree()

{

this.root = null;

numberElement = 0;

}// End of default constructor

// Method to insert key

public void insert(int key)

{

// Creates a node using parameterized constructor

TreeNode newNode = new TreeNode(key);

numberElement++;

// Checks if root is null then this node is the first node

if(root == null)

{

// root is pointing to new node

root = newNode;

return;

}// End of if condition

// Otherwise at least one node available

// Declares current node points to root

TreeNode currentNode = root;

// Declares parent node assigns null

TreeNode parentNode = null;

// Loops till node inserted

while(true)

{

// Parent node points to current node

parentNode = currentNode;

// Checks if parameter key is less than the current node key

if(key < currentNode.key)

{

// Current node points to current node left

currentNode = currentNode.left;

// Checks if current node is null

if(currentNode == null)

{

// Parent node left points to new node

parentNode.left = newNode;

return;

}// End of inner if condition

}// End of outer if condition

// Otherwise parameter key is greater than the current node key

else

{

// Current node points to current node right

currentNode = currentNode.right;

// Checks if current node is null

if(currentNode == null)

{

// Parent node right points to new node

parentNode.right = newNode;

return;

}// End of inner if condition

}// End of outer if condition

}// End of while

}// End of method

// Method to check tree is balanced or not

private int checkBalance(TreeNode currentNode)

{

// Checks if current node is null then return 0 for balanced

if (currentNode == null)

return 0;

// Recursively calls the method with left child and

// stores the return value as height of left sub tree

int leftSubtreeHeight = checkBalance(currentNode.left);

// Checks if left sub tree height is -1 then return -1

// for not balanced

if (leftSubtreeHeight == -1)

return -1;

// Recursively calls the method with right child and

// stores the return value as height of right sub tree

int rightSubtreeHeight = checkBalance(currentNode.right);

// Checks if right sub tree height is -1 then return -1

// for not balanced

if (rightSubtreeHeight == -1) return -1;

// Checks if left and right sub tree difference is greater than 1

// then return -1 for not balanced

if (Math.abs(leftSubtreeHeight - rightSubtreeHeight) > 1)

return -1;

// Returns the maximum value of left and right subtree plus one

return (Math.max(leftSubtreeHeight, rightSubtreeHeight) + 1);

}// End of method

// Method to calls the check balance method

// returns false for not balanced if check balance method returns -1

// otherwise return true for balanced

public boolean balanceCheck()

{

// Calls the method to check balance

// Returns false for not balanced if method returns -1

if (checkBalance(root) == -1)

return false;

// Otherwise returns true

return true;

}//End of method

// Method for In Order traversal

public void inorder()

{

inorder(root);

}//End of method

// Method for In Order traversal recursively

private void inorder(TreeNode root)

{

// Checks if root is not null

if (root != null)

{

// Recursively calls the method with left child

inorder(root.left);

// Displays current node value

System.out.print(root.key + " ");

// Recursively calls the method with right child

inorder(root.right);

}// End of if condition

}// End of method

}// End of class BinaryTree

// Driver class definition

class BalancedBinaryTreeCheck

{

// main method definition

public static void main(String args[])

{

// Creates an object of class BinaryTree

BinaryTree treeOne = new BinaryTree();

// Calls the method to insert node

treeOne.insert(1);

treeOne.insert(2);

treeOne.insert(3);

treeOne.insert(4);

treeOne.insert(5);

treeOne.insert(8);

// Calls the method to display in order traversal

System.out.print("\n In order traversal of Tree One: ");

treeOne.inorder();

if (treeOne.balanceCheck())

System.out.println("\n Tree One is balanced");

else

System.out.println("\n Tree One is not balanced");

BinaryTree

BinaryTree treeTwo = new BinaryTree();

treeTwo.insert(10);

treeTwo.insert(18);

treeTwo.insert(8);

treeTwo.insert(14);

treeTwo.insert(25);

treeTwo.insert(9);

treeTwo.insert(5);

System.out.print("\n\n In order traversal of Tree Two: ");

treeTwo.inorder();

if (treeTwo.balanceCheck())

System.out.println("\n Tree Two is balanced");

else

System.out.println("\n Tree Two is not balanced");

}// End of main method

}// End of driver class

5 0
3 years ago
Write a C++ program that computes the area and perimeter of aspecified shape
leonid [27]

<u>C++ program that computes the area and perimeter of a specified shape</u>

#include <iostream>

#include <cmath>

using namespace std;

void rectangle() //Defining function for rectangle

{ int h,w;

cout << "Enter height: ";

//taking input

cin >> h;

cout << "Enter width: ";

cin >> w;

cout << "The perimeter of the rectangle is " <<2*h+ 2*w << " and the area is " <<h*w << endl;  //printing output

}

void triangle()  //Defining function for triangle

{ int s1,s2,s3,h,w;

cout << "Side 1: ";  //Taking input

cin >> s1;

cout << "Side 2: ";

cin >> s2;

cout << "Side 3: ";

cin >> s3;

cout << "Enter the height: ";

cin >> h;

cout << "Enter the base length: ";

cin >> w;

cout << "The perimeter of the triangle is " <<s1+s2+s3 << " and the area is " <<(.5)*w*h << endl; //printing output

}

void circle()//Defining Function for the circle

{

const double p=3.14;

int w;

cout << "Enter the radius: "; //Taking input

cin >> w;

cout << "The perimeter of the circle is " << p*2*w << " and the area is " << p*w*w<< endl;  //printing output

}

int main()  //driver function

{

int s;

cout << "Enter the shape (1 for rectangle,2 for triangle, 3 for circle): ";

//Asking user for the shape

cin >> s;

switch(s)  //checking which shape it chooses

{

case 1:

rectangle();  //If user type 1 ,then calling rectangle function

break;

case 2:

triangle();   //If user type 2 ,then calling triangle function

break;

case 3:

circle();  //If user type 3,then calling circle function

break;

default:

cout <<"Enter valid choice for shape";  //If user type other than 1,2,3

}

return 0;  

}

<u>Output</u>

Enter the shape (1 for rectangle,2 for triangle, 3 for circle): 1

Enter height:2

Enter width: 3

The perimeter of the rectangle is 10 and the area is 6

<u />

4 0
3 years ago
A three-character code is to be assigned only if it cannot be further subdivided, and a code is __________ if it has not been co
pav-90 [236]

Answer:

Invalid are the correct answer to the following statement.

Explanation:

The following statement is correct because the following code is invalid if the code is not summarized properly according to the requirement of the following code in which the seventh character extension is included, if the three-character code is not be subdivided any more then, the following code is invalid.

5 0
3 years ago
What do you type into an empty cell to start a formula?
Pepsi [2]

Answer:The formula in MS Excel begins with an equal sign (=). ...

Constants, such as numerals or text values, can be directly entered into a formula.

Operators define the type of calculation that the formula executes.

Explanation: here hope it helps

8 0
2 years ago
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