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2 years ago

On a piece of paper, use a protractor to construct right triangle ABC with BC=5 cm, m∠B=60°, and m∠C=90°.

Mathematics

1 answer:

Allushta [10]2 years ago

4 0

Answer: D.

Step-by-step explanation

i took the test im 100% percent sure that im right if im not im really sorry

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Can anyone help with this question pleasee

Vladimir [108]

Answer:

$y = 1$

Step-by-step explanation:

Given:

$a^{3y - 5} = \frac{1}{a^2}$

Apply the negative exponent rule

$a^{3y - 5} = a^{-2}$

The bases will cancel each other

$3y - 5 = -2$

$3y - 5 + 5 = -2 + 5$

$3y = 3$

$\frac{3y}{3} = \frac{3}{3}$

$y = 1$

7 0

3 years ago

Escreva uma equação do 2 grau que tenha: a) - 5 e 3 como raízes. b) x, +x, = 17 x, x = 70, sabendo que x, e x, são as raízes. =

umka21 [38]

Can u translate in English for me

7 0

2 years ago

Complete the table of values for the linear relation y = -5x + 10.

musickatia [10]

the answer will be -5

Step-by-step explanation:

because you have to minus 5 and 10

so the answer will be x =- 5

3 0

2 years ago

Which ordered pair is a solution to the system of inequalities shown on the graph?

wolverine [178]

Answer:

5,2

Step-by-step explanation:

Here, we want to find the point that is a solution to the system of inequalities

From what we have, the points that lie in the dark brown patch represent the solution to the system

Hence the coordinates lying in these parts are the solution to the system

An example of such coordinates is the point (5,2)

7 0

3 years ago

Un agricultor tiene un terreno cuadrado dedicado al cultivo de hortalizas. Para ampliarlo, quiere comprar el terreno adyacente,

Agata [3.3K]

Answer: 20 meters.

Step-by-step explanation:

The formula for calculate the area of a square is:

$A=s^2$

Where "s" is the side length of the square:

The formula for calculate the area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

Based on the information provided, you know the sum of the areas of the square land and the adjacent land is 600 m². This is:

$A_1+A_2=600\\\\s^2+lw=600$

Knowing that the width of the adjacent land is 10 meters:

$s^2+10l=600$

Since the lenght of the adjacent land and the side lenght of his actual land are equal:

$l=s$

You can substitute this into $s^2+10l=600$ :

$s^2+10s=600\\\\s^2+10s-600=0$

Applying the Quadratic formula, you get:

$s=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\\\s=\frac{-10\±\sqrt{(10)^2-4(1)(-600)} }{2(1)}\\\\s_1=20\\\\s_2=-30$

Since the side lenght cannot be negative, you can determine that this is:

$s=20\ m$

7 0

3 years ago