Algebra question please help

Anne deposited $500 in an account that earns 6% simple annual interest. Shelly deposited $500 in an account that earns 6% annual

Inga [223]

Answer:

It is clear that, The Shelly account is $11.23 more than that in Anne account .

Step-by-step explanation:

Given as :

For Anne

The amount deposited in account = p = $500

The rate of interest = r = 6% at simple interest

The time period of deposit = t = 4 years

Let The amount received in account after 4 years = $ $A_1$

<u>From Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, s.i = $\dfrac{\textrm 500\times \textrm 6\times \textrm 4}{100}$

Or, s.i = $\dfrac{12000}{100}$

i.e s.i = $120

∵ Amount = Principal + Interest

Or, $A_1$ = p + s.i

Or $A_1$ = $500 + $120

Or, Amount = $620

So, The Amount in Anne account after 4 years is $620

Again

For, Shelly

The amount deposited in account = P = $500

The rate of interest = R = 6% compounded annually

The time period of deposit = T = 4 years

Let The amount received in account after 4 years = $ $A_2$

<u>From Compound Interest method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, $A_2$ = P × $(1+\dfrac{\textrm R}{100})^{\textrm T}$

Or, $A_2$ = $500 × $(1+\dfrac{\textrm 6}{100})^{\textrm 4}$

Or, $A_2$ = $500 × $(1.06)^{4}$

Or, $A_2$ = $500 × 1.26247

Or, $A_2$ = $631.23

So, The amount received by Shelly in her account after 4 years = $631.23

Now, Difference between amount received in their account

i.e $A_2$ - $A_1$ = $631.23 - $620

Or, $A_2$ - $A_1$ = $11.23

Hence, It is clear that, The Shelly account is $11.23 more than that in Anne account . Answer

8 0

3 years ago

Answer these 2 Questions for 10 points

Hitman42 [59]

29 x 13= 3720 x 1= 3720 divide that by 10= 372 remove 3 so (7,2) is the slope roach

6 0

3 years ago

Which of the following is an example of inverse operations?

kkurt [141]

Answer:

12^2 and 12/3

Step-by-step explanation:

Examples of inverse operations are: addition and subtraction; multiplication and division; and squares and square roots.

4 0

3 years ago

Read 2 more answers

Jamie is hiking up a small mountain. He climbs up at a constant rate of 300 feet/hour until he reaches the peak at 1,500 feet. A

aleksandr82 [10.1K]

Answer:

a. d = 1500 - 300t. b. after 2 hours and after 4 hours

Step-by-step explanation:

a. Since Jamie hikes up the mountain at a rate of 300 ft/hr, and the mountain is 1500 ft high, his distance, d from the peak of the mountain at any given time,t is given by

d = 1500 - 300t.

b.If Jamie distance d = 900 ft, then the equation becomes,

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

The equation d = 1500 - 300t. also models his distance from the peak of the mountain if he hikes down at a constant rate of 300 ft/hr

At d = 900 ft, the equation becomes

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

So, on his hike down the mountain, it takes him another 2 hours to be 900 ft from the peak of the mountain.

So, he is at 900 ft on his hike down after his start of hiking up the mountain at time t = (2 + 2) hours = 4 hours. Since it takes 2 hours to climb to the peak of he mountain and another 2 hours to climb down 900 ft from the peak of the mountain.

4 0

3 years ago

Please help! :)

Volgvan

Answer:

So the correct option is First one

i.e $\dfrac{9\pi}{A}=\dfrac{90}{360}$