Answer:
x < -4 or x > 7.
Step-by-step explanation:
We first determine the critical points by solving x^2 - 3x - 28 = 0:
x^2 - 3x - 28 = 0
(x - 7)(x + 4) = 0
x = 7, - 4
so the critical points are -4 and 7.
Create a Table (pos = positive and neg = negative):
Value of x< - 4 -4 < x < 7 x > 7
---------------------|----------- |--------------------- |---------------------
x + 4 NEG POS POS
x - 7 NEG NEG POS
(x + 4)(x - 7) POS NEG POS
So the function is positive (>0) for x < -4 or x > 7.
You can also do this by drawing the graph of the function.
136 should be your answer
Since you subtract 6 and you have to find the sixth term, you can do:
-6×5=-30 ( negative shows you're subtracting and since 75 is the first term, then you have to find the difference of the input/term 6-1, the sixth term minus the first)
75-30=45
You can check by actually continuing the pattern.
75,69,63,57,51,45,39......
Answer:
d = 244
Step-by-step explanation:
1) Change radical forms to fractional exponents using the rule:The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (

) = 3 to the one-half power (

).
The 5th root of 3 (
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (

).
2) Now use the product of powers exponent rule to simplify:This rule says

. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have

. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
------
Answer:
or