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fgiga [73]
2 years ago
9

A particular shoe store stocks two styles of walking shoes. Style A sells for $66.95 and Style B sells for $84.95. At the end of

the week, sales totaled in $17,652. The number of Style A shoes sold was twenty-four less than twice the number of Style B shoes sold. how many of each type or so that week?
Mathematics
1 answer:
Gnom [1K]2 years ago
8 0

Answer:

Style A shoes sold : <u>152</u>

Style B shoes sold : <u>88</u>

Step-by-step explanation:

Let :

  • Style A shoes = x
  • Style B shoes = y

Forming equations :

  1. x = 2y - 24
  2. 66.95x + 84.95y = 17,652

Substitute the value of x from 1 in 2.

  • 66.95 (2y - 24) + 84.95y = 17,652
  • 133.90y - 1606.80 + 84.95y = 17,652
  • 218.85y = 19258.80
  • <u>y = 88</u>

<u />

Finding x :

  • x = 2(88) - 24
  • x = 176 - 24
  • <u>x = 152</u>

<u />

Solution :

  • Style A shoes sold : <u>152</u>
  • Style B shoes sold : <u>88</u>
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Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50
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Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

\texttt{ }

<em>Jaces songs were played on 6 more commercials than movies.</em>

\boxed{C = 6 + M} → <em>Equation 1</em>

\texttt{ }

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

\boxed{50C + 140M = 680} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1  ↔ Equation 2 :</em>

50C + 140M = 680

50 ( 6 + M ) + 140M = 680

300 + 50M + 140M = 680

190M = 680 - 300

190M = 380

M = 380 \div 190

M = 2

\texttt{ }

C = 6 + M

C = 6 + 2

C = 8

\texttt{ }

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0
3 years ago
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