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2 years ago

What is the value of 7x-3y-1 for x = -2 and y = 4?

Mathematics

2 answers:

egoroff_w [7]2 years ago

6 0

7(2 - 3) 4 - 1
7 •(1) • 4 - 1
-28 - 1
-29

vova2212 [387]2 years ago

5 0

$\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}$

<em> what is the value of 7x-3y-1 for x = -2 and y = 4?</em>

<em />

<em /> $\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}$

Replace x with -2 and y with 4:-

$\sf{7(-2)-3(4)-1}$

On simplification,

$\sf{-14-12-1}$

On further simplification,

$\sf{-27}$

<h3>Good luck with your studies.</h3>

$\rule{300}{1}$

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3/8 x 2/6 x 4/8 x 5/12

Hatshy [7]

Answer:

$\frac{5}{192}$

Step-by-step explanation:

$\frac{3}{8}*\frac{2}{6}*\frac{4}{8}*\frac{5}{12}\\\\\frac{3}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{12}\\\\\frac{1}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{4}\\\\\frac{5}{192}$

7 0

3 years ago

PLEASE HELP!! I’m very confuse

SVETLANKA909090 [29]

Given:

A(16, 4)

B(34, 40)

Line segment AB partition in the ratio 1 : 5.

To find:

The coordinate of a point that partitions AB.

Solution:

Section formula:

$$P(x,y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}\right)$

Here $x_1=16, y_1=4, x_2=34, y_2=40$ and m = 1, n = 5

$$P(x,y)=\left(\frac{1\times 34+5 \times 16}{1+5}, \frac{1\times 40+5 \times4}{1+5}\right)$

$$P(x,y)=\left(\frac{ 34+80}{6}, \frac{40+20}{6}\right)$

$$P(x,y)=\left(\frac{ 114}{6}, \frac{60}{6}\right)$

$$P(x,y)=(19, 10)$

The coordinate of point that partitions the segment AB is (19, 10).

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3 years ago

Initial Knowledge Check

Anna [14]

Answer:

becos i know UwU

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3 years ago

Solve equation <br> 0.3 :4=9:y

elixir [45]

Answer:

You should use photomath, it would be more easier for u. Oh, and by the watñy Y=12

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3 years ago

A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav

Vedmedyk [2.9K]

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

6 0

3 years ago