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Naya [18.7K]
2 years ago
5

What is the value of 7x-3y-1 for x = -2 and y = 4?

Mathematics
2 answers:
egoroff_w [7]2 years ago
6 0
7(2 - 3) 4 - 1
7 •(1) • 4 - 1
-28 - 1
-29
vova2212 [387]2 years ago
5 0

\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

<em>           what is the value of 7x-3y-1 for x = -2 and y = 4?</em>

<em />

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

Replace x with -2 and y with 4:-

\sf{7(-2)-3(4)-1}

On simplification,

\sf{-14-12-1}

On further simplification,

\sf{-27}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

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3/8 x 2/6 x 4/8 x 5/12
Hatshy [7]

Answer:

\frac{5}{192}

Step-by-step explanation:

\frac{3}{8}*\frac{2}{6}*\frac{4}{8}*\frac{5}{12}\\\\\frac{3}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{12}\\\\\frac{1}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{4}\\\\\frac{5}{192}

7 0
3 years ago
PLEASE HELP!! I’m very confuse
SVETLANKA909090 [29]

Given:

A(16, 4)

B(34, 40)

Line segment AB partition in the ratio 1 : 5.

To find:

The coordinate of a point that partitions AB.

Solution:

Section formula:

$P(x,y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}\right)

Here x_1=16, y_1=4, x_2=34, y_2=40 and m = 1, n = 5

$P(x,y)=\left(\frac{1\times 34+5 \times 16}{1+5}, \frac{1\times 40+5 \times4}{1+5}\right)

$P(x,y)=\left(\frac{ 34+80}{6}, \frac{40+20}{6}\right)

$P(x,y)=\left(\frac{ 114}{6}, \frac{60}{6}\right)

$P(x,y)=(19, 10)

The coordinate of point that partitions the segment AB is (19, 10).

4 0
3 years ago
Initial Knowledge Check
Anna [14]

Answer:

0

5

3

becos i know UwU

5 0
3 years ago
Solve equation <br> 0.3 :4=9:y
elixir [45]

Answer:

You should use photomath, it would be more easier for u. Oh, and by the watñy Y=12

3 0
3 years ago
A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav
Vedmedyk [2.9K]

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

6 0
3 years ago
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