In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.
So, you can find multiple values that meet this:
y = kx => k = y / x = 11 / 18
=> y = (11/18)x
Now you can give any value to x and fint the value of x that satisfy the relationship:
x y = (11/18)x
1 11/18
2 11/18 * 2 = 11/9
18 11/18 * 18 = 11
36 11/18 * 36 = 22
So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
Answer: 96 ways
In this case, the freshman must take one class each from Science(6 courses), Humanities(4 courses) and Mathematics( 4 courses).
Then to know how many ways she can arrange you just need to multiply the each course count (it would different if she has to take more than one class).
The calculation would be: 6 x 4 x 4= 96 ways.
Answer:
45
Step-by-step explanation:
To know how many 1/5 s are in 9, we will take the ratio of both numbers as shown;
9:1/5
= 9 ÷ 1/5
= 9 * 5/1
= 9 * 5
= 45
Hence there are 45 1/5s in 9
3(x+2) < 10 //// that should be right!!
