3+<img src="https://tex.z-dn.net/?f=3%2B%5Csqrt%7B2%7D%2F4%5Csqrt%7B2%7D%2B2" id="TexFormula1" title="3+\sqrt{2}/4\sqrt{2}+2" al

Emi buys 14 balloons. Three are red, four are white, and the rest are blue. Hat is the ratio of blue balloons to the total numbe

Deffense [45]

Answer:

The ratio of blue balloons to the total number of balloons is 1:2.

Step-by-step explanation:

Given:

Total number of balloons = 14

Number of red balloons = 3

number of white balloons = 4

Number of the blue balloons are the rest remaining.

We need to find the the ratio of blue balloons to the total number of balloons.

Solution:

First we will find the number of blue balloons.

Now we know that;

Number of the blue balloons can be calculated by Total number of balloons minus sum of Number of red balloons and number of white balloons.

framing in equation form we get;

Number of the blue balloons = $14-(3+4) =14 -7 =7$

Now to find the ratio of blue balloons to the total number of balloons we will divide Number of the blue balloons from Total number of balloons.

framing in equation form we get;

Ratio = $\frac{7}{14} = \frac{7\times1}{7\times2}= \frac{1}{2}$

Hence the ratio of blue balloons to the total number of balloons is 1:2.

8 0

4 years ago

Write the absolute value inequality in the form x−b ≤c or x−b ≥c that has the solution set −1≤x≤3.

stealth61 [152]

Answer:

|x - 1| ≤ 2

Step-by-step explanation:

b = (-1+3)/2 = 1

c = 3-1 = 2

|x - 1| ≤ 2

4 0

3 years ago

Find a point on the y-axis that is equidistant from the points (8, −8) and (1, 1).

artcher [175]

$\text{We know that any point on the y-axis is of the form (0, y),}\\
\text{because on y-axis we have x=0.}\\
\\
\text{So let (0, y) be the point on the y-axis that is equidistance from}\\
\text{the points }(8,-8) \text{ and }(1,1)\\
\\
\text{so using the distance formula, we have}\\
\\
\text{Distance between (0, y) and }(8,-8)=\text{Distance between (0,y) and }(1,1)\\
\\
\Rightarrow \sqrt{(0-8)^2+(y-(-8))^2}=\sqrt{(0-1)^2+(y-1)^2}$

$\Rightarrow \sqrt{64+(y+8)^2}=\sqrt{1+(y-1)^2}\\
\\
\text{Squaring both sides, we get}\\
\\
(\sqrt{64+(y+8)^2})^2=(\sqrt{1+(y-1)^2})^2\\
\\
\Rightarrow 64+(y+8)^2=1+(y-1)^2\\
\\
\Rightarrow 64+(y^2+16y+64)=1+(y^2-2y+1)\\
\\
\Rightarrow y^2+16y+128=y^2-2y+2\\
\\
\Rightarrow y^2+16y-y^2+2y=2-128\\
\\
\Rightarrow 18y=-126\\
\\
\Rightarrow y=\frac{-126}{18}\\
\\
\Rightarrow y=-7$