2 1/2 mi = blank feet

Maslowich

I don't understand the question

5 0

3 years ago

An account earns simple interest. $300 at 4% for 3 years a. Find the interest earned. $ b. Find the balance of the account. $

aliina [53]

A. take 300*0.04*3 which is $36

b. add $36 to $300

5 0

3 years ago

Read 2 more answers

Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H.Which sequence of

Tasya [4]

Answer:

the answer is A

Step-by-step explanation:

hope it worked

3 0

3 years ago

Read 2 more answers

Help me out? it would mean tons tysm

m_a_m_a [10]

Answer:

y - 5 = -3(x + 2)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Step-by-step explanation:

Step 1: Define

Slope m = -3

Point (-2, 5)

Step 2: Write function

Substitute: y - 5 = -3(x + 2)

3 0

3 years ago

] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was

Bad White [126]

Answer:

$z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930$

The p value for this case would be given by:

$p_v =P(z>3.930)=0.0000443$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

$\hat p=\frac{502}{1045}=0.480$ estimated proportion of college graduates with a mentor

$p_o=0.42$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:

Null hypothesis: $p \leq 0.42$

Alternative hypothesis: $p > 0.42$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930$

The p value for this case would be given by:

$p_v =P(z>3.930)=0.0000443$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0

3 years ago