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Gwar [14]
2 years ago
6

1. Explain the Law of Cosines by ∆ ABC

Mathematics
2 answers:
seropon [69]2 years ago
7 0
<h3>TRIGONOMETRY</h3>

===================================

1.) Explain the Law of Cosines by ∆ ABC

  • \begin{gathered}\sf{{a ^ 2 = b ^ 2 + c ^ 2 - 2bc(cos A)}}\\ \sf{{b ^ 2 = a ^ 2 + c ^ 2 - 2ac(cos B)}} \\ \sf{{c ^ 2 = a ^ 2 + b ^ 2 - 2ab(cos C)}}\end{gathered}

2.) Explain Law of Sines by ∆ ABC

  • \sf{{\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}}}

3.) Explain The SSA ( There is no SSA postulate so you may have just typed the question incorrectly or you may be asking about SSA Possibilities.)

» SSA ( Side-Side-Angle) · the two triangles are equal if two sides and an angle not included between them are equal.

<h3>The SSA Possibilities:</h3>

  • If ∠A is an acute angle and a≥b, then there is exactly one solution.

  • If ∠A is an obtuse or a right angle and a≤b, then there is exactly no solution.

  • If ∠A is an acute angle, a<b, and a=b sin A then there is exactly one solution.

  • If ∠A is an obtuse or a right angle and a>b, then there is exactly one solution.

===================================

#LetEarthBreathe

ZanzabumX [31]2 years ago
6 0
<h3>Question :</h3>

Law of Cosines by ∆ ABC

\\  \\

<h3>Answer :</h3>

\\

<u>Law of Cosines by ∆ </u><u>ABC:</u>

<em>Let three side be</em> :

  • a
  • b
  • c

\\

<em>Formula</em>:

  • a² = b² + c² – 2bc (cos A)
  • b² = a² + c² – 2ac (cos B)
  • c² = b² + a² – 2ba (cos C)

\\

<em>Also </em><em>known</em><em> </em><em>as </em><em>:</em>

Law of Cosines by ∆ ABC is also known as :

  • cosine rule

\\

<em>Define</em><em> </em><em>:</em>

The law of cosines states that if any two sides(i.e a , b , or c) of a triangle and angle formed between them ( i.e ∠A , ∠B or ∠C) are give then we are able to find third side.

(side 1)² = (side 2)² + (side 3)² - 2 side 1 × side 2 (cos angle formed between side 2 and side 3)

\blue{ \huge \underline{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

<h3>Question :</h3>

Law of Sines by ∆ ABC

\\  \\

<h3>Answer :</h3>

\\

<u>Law of sines by ∆ ABC:</u>

<em>Let three side be :</em>

  • a
  • b
  • c

\\

<em>Formula</em><em> </em><em>:</em>

\boxed{ \rm \frac{a}{ \sin(A) } =  \frac{b}{ \sin(B) } =  \frac{c}{ \sin(C) } }

\\

<em>Define</em><em> </em><em>:</em>

It is ratio between side of triangle (i.e a , b , c) and sin of angle formed (angle A , angle B or angle C) opposite to it. Above formula you can see side a is side angle and opposite angle sin i.e A are in ratio and they are equal to ratio of side b and sin of opposite angle to b i.e angle B.

\blue{ \huge \underline{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

<em>Correct</em><em> </em><em>Question</em><em> </em><em>:</em>

Explain SSA

\\

<em>Full </em><em>form</em>

S - Side

S - Side

A - Angle

\\

<em>Define :</em>

This condition is seen when two triangles are congruent , when two sides are equal and angle which is not formed between them are equal.

\\

<em>Congruent</em><em> </em><em>triangles</em><em> </em><em>:</em>

Congruent triangles are those triangles that have exact shape and size.

\\

<em>Conditions </em><em>for </em><em>congruent</em><em> </em><em>triangles</em><em> </em><em>:</em>

  • SAS

Side - angle - side

  • ASA

angel - side - angle

  • SSA

side side angle

  • SSS

side side side

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A teacher spends $354 on costumes and microphones for six cast members in a play. Each cast member receives a costume that costs
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The teacher spend some amount on buying costumes and microphones for 6 cast members.

<u>GiveN</u><u>:</u>

  • Cost of each costume = $38
  • Cost of each microphone = $c
  • Total money spent = $354

Let's frame the equation. Total money is the total amount spent for 6 cast members.

Money spent on costumes = $38 × 6

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<u>Equation:</u>

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Taking 6 as common,

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Dividing 6 from both sides,

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The teacher spent this much on each microphone.

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

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