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Helen [10]
3 years ago
13

HELP PLEASE!⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0
He messed up in the beginning with the 4.

It's supposed to be
(3 - -4)
(3 + 4)

and not

(3-4)

That's where he messed up.




I find it interesting how he uses Xa Ya and Xb Yb. In my school we use X1 Y1 and X2 Y2.
You might be interested in
What is the cordniate for (-6, -23)?​
Hatshy [7]

Answer:

Step-by-step explanation:

A set of values that show an exact position. On graphs it is usually a pair of numbers: the first number shows the distance along, and the second number shows the distance up or down.

5 0
3 years ago
6. To predict the annual rice yield in pounds we use the equation y-hat = 859 + 5.76x1 + 3.82x2 where x1 represents the number o
zysi [14]
The yield is given by the regression equation
y = 859 + 5.76x₁ + 3.82x₂ 
where
x₁ = number of acres planted
x₂ = number of acres harvested

The goodness of fit is r² = 0.94.
This appears to a very good fit to the data because it is almost equal to 1.
To assess the goodness of fit in a statistical sense, it may also necessary to perform an F-test in a hypothesis test. This is not possible without having raw measured data.
For this problem, r²=0.94 may be considered to be a very good fit to the measured data.

Part a.
When x₁ = 3200 acres and x₂ = 3000 acres, obtain
y = 859 + 5.76*3200 + 3.82*3000
   = 30,751 pounds

Part b.
Without performing a hypothesis test or a residual plot, we can conclude that the predicted value is in very good agreement with the actual value.

Because we do not have raw measured data, we can neither plot the residuals nor perform a hypothesis test.

In general,
When r² = 1, the agreement is exact.
When r² = 0, there is absolutely no agreement.
A value of r² > 0.9 is considered good.


3 0
3 years ago
Using linked lists or a resizing array; develop a weighted quick-union implementation that removes the restriction on needing th
balu736 [363]

Answer:

Step-by-step explanation:

package net.qiguang.algorithms.C1_Fundamentals.S5_CaseStudyUnionFind;

import java.util.Random;

/**

* 1.5.20 Dynamic growth.

* Using linked lists or a resizing array, develop a weighted quick-union implementation that

* removes the restriction on needing the number of objects ahead of time. Add a method newSite()

* to the API, which returns an int identifier

*/

public class Exercise_1_5_20 {

public static class WeightedQuickUnionUF {

private int[] parent; // parent[i] = parent of i

private int[] size; // size[i] = number of sites in subtree rooted at i

private int count; // number of components

int N; // number of items

public WeightedQuickUnionUF() {

N = 0;

count = 0;

parent = new int[4];

size = new int[4];

}

private void resize(int n) {

int[] parentCopy = new int[n];

int[] sizeCopy = new int[n];

for (int i = 0; i < count; i++) {

parentCopy[i] = parent[i];

sizeCopy[i] = size[i];

}

parent = parentCopy;

size = sizeCopy;

}

public int newSite() {

N++;

if (N == parent.length) resize(N * 2);

parent[N - 1] = N - 1;

size[N - 1] = 1;

return N - 1;

}

public int count() {

return count;

}

public int find(int p) {

// Now with path compression

validate(p);

int root = p;

while (root != parent[root]) {

root = parent[root];

}

while (p != root) {

int next = parent[p];

parent[p] = root;

p = next;

}

return p;

}

// validate that p is a valid index

private void validate(int p) {

if (p < 0 || p >= N) {

throw new IndexOutOfBoundsException("index " + p + " is not between 0 and " + (N - 1));

}

}

public boolean connected(int p, int q) {

return find(p) == find(q);

}

public void union(int p, int q) {

int rootP = find(p);

int rootQ = find(q);

if (rootP == rootQ) {

return;

}

// make smaller root point to larger one

if (size[rootP] < size[rootQ]) {

parent[rootP] = rootQ;

size[rootQ] += size[rootP];

} else {

parent[rootQ] = rootP;

size[rootP] += size[rootQ];

}

count--;

}

}

public static void main(String[] args) {

WeightedQuickUnionUF uf = new WeightedQuickUnionUF();

Random r = new Random();

for (int i = 0; i < 20; i++) {

System.out.printf("\n%2d", uf.newSite());

int p = r.nextInt(i+1);

int q = r.nextInt(i+1);

if (uf.connected(p, q)) continue;

uf.union(p, q);

System.out.printf("%5d-%d", p, q);

uf.union(r.nextInt(i+1), r.nextInt(i+1));

}

}

}

8 0
3 years ago
True or False?<br> -2.08 would be just to the right of -2 on the number line.
Gennadij [26K]
It is False because negative as good to the left
3 0
3 years ago
Andre wants to run ten miles in three days. He ran 2.5 miles on Monday and 4.4 miles on Tuesday. How many miles does Andre need
Daniel [21]

Answer:

3.1 miles

Step-by-step explanation:

2.5 + 4.4 = 6.9

10 - 6.9 = 3.1

4 0
3 years ago
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