Mimiwhatsup Answer is: H
The graph is correct and so is the table it's domain and ranges are correct I know I is not correct hope this helps!
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Well, there are 52 cards in a deck, with 4 suits. there is a Jack and queen per suit, so that is a total of 8 jacks and queens in the deck. that probability looks like 8:52 as a ratio, or 2:13 simplified. so, you are likely to draw a Jack or queen 8 out of 52 times, or 2 out of 13 times
