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2 years ago

Find the surface area.

Mathematics

2 answers:

Serga [27]2 years ago

6 0

Answer:

88 $m^{2}$

Step-by-step explanation:

The surface are is the total area of all the faces

Opposite faces have the same area

Label each side either l, h or w

SA of a cuboid = 2lw + 2lh + 2hw

(2 x 4 x 6) + (2 x 4 x 2) + (2 x 6 x 2) = 8

gulaghasi [49]2 years ago

4 0

Answer:

do you want to me to find it for all or just 1

You might be interested in

a bag of flour contains 8 cups of flour a batch of cookies requires 1 2/5 cups of flour how many batches of cookies can you make

Nataliya [291]

Put 8 into fraction form: 8/1

Put 1 2/5 into a mixed number: 1*5+2 as numerator and 5 as denominator (7/5)

Now multiply 8/1 by the reciprocal of 7/5, which is basically just the numerator and denominator flipped, so 5/7. This is like dividing.

8/1*5/7= 40/7

40/7= about 5.7.

So, your answer would be 5.7 batches, or 5 complete batches would be a better answer.

8 0

3 years ago

NEED HELP! GIVING POINTS!

serg [7]

Answer:

Step-by-step explanation:

fairly certain it is b

6 0

3 years ago

Read 2 more answers

9=10 8=18 7=24 6=28 5=30 3=??

natima [27]

Answer:

28.5

Step-by-step explanation:

This is because each number increases by half of the previous number,

the difference between 10 and 18 is eight, which when halved is 4,

the difference between 18 and 24 is four, the pattern then carries on...

Hopefully you found this useful :)

7 0

4 years ago

I'll give brainliest to whoever answers the question correctly!!!!

Leni [432]

Answer:

Is it statement 3? It looks like it doesn't belong.

6 0

2 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago