Question

The equation d = 16t^2 gives the distance d in feet that a golf ball falls in t seconds. How many seconds will it take a golf ball to drop to the ground from a height of 4 feet? 64 feet?

Answer 1

Answer: 0.5 seconds for 4 ft and 2 seconds for 64 ft

d=16t^2

4=16t^2

/16  /16

t^2=1/4

t=1/2

0.5 seconds for 4 ft

64 = 16t^2

/16    /16

4=x^2

x=2

2 seconds for 64 ft