The equation d = 16t^2 gives the distance d in feet that a golf ball falls in t seconds. How many seconds will it take a golf ba
ll to drop to the ground from a height of 4 feet? 64 feet?
1 answer:
Answer: 0.5 seconds for 4 ft and 2 seconds for 64 ft
d=16t^2
4=16t^2
/16 /16
t^2=1/4
t=1/2
0.5 seconds for 4 ft
64 = 16t^2
/16 /16
4=x^2
x=2
2 seconds for 64 ft
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