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Luden [163]
3 years ago
8

2. Solve the quadratic equation by completing the square.

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

The roots of the quadratic equation are:

x = 0.74 - 0.6614i

x = 0.74 + 0.6614i

The given equation is:

2x² + 2 = 3x

Rearrange the equation

2x² -3x = -2

Divide through by 2

x² - (3/2)x = -1

x² - (3/2)x + (3/4)² = -1 + (3/4)²

(x - 3/4)² = -7/16

Square root both sides

x - 3/4 = √(-7/16)

x = 3/4 ± √(-7) / 4

x = 0.75 ± i√(7) / 4

x = 0.74 ± 0.6614i

Therefore, the roots of the quadratic equation are:

x = 0.74 - 0.6614i

x = 0.74 + 0.6614i

Learn more here: brainly.com/question/13981588

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What you gotta take from this problem:

What Joe got during break = 2t+2

What his sister gave him = 3t

What he has total = 10 tadpoles.


Now to assemble this equation:

2t+2+3t=10

Now combine like terms to get 5t+2=10

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7 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
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