1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tresset_1 [31]
3 years ago
15

This net folds into a cube. Which two letters appear on opposite faces?

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

Three answers B and D, A and C, F and E

I'm not very sure how to explain this.

You might be interested in
Students in Mr. Rivas’ class were practicing their multiplication skills by rolling three 6-sided number cubes. Chris rolled a 2
guajiro [1.7K]

Sorry wrote down the wrong thing the first time. Try doing 2 plus 3 times 5.

3 0
3 years ago
Read 2 more answers
Which function has a vertex on the y-axis?
andre [41]
F(x) = (x - 2)(x + 2)
7 0
3 years ago
Any number that is divisible by 3 is also divisible by 6 find a counter example to show that the conjecture is false.
finlep [7]

Answer:

the answer is very simple: 21

7 0
4 years ago
Solve 12ds/w=CD for w.
denis23 [38]
Divide 12 on both sides
ds/w=cd/12
now multiply ds on both sides
w=cd/12ds
4 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Other questions:
  • Problem:
    15·1 answer
  • 4.(7.03 mc).
    12·1 answer
  • Translate the following points 5 units up (-5,-2) (-2,1) (-4,-7)
    7·1 answer
  • Prove this polynomial identity...<br><br> (x − y)(x2 + 2xy + y2)
    11·1 answer
  • Which expression has a value less than the given expression when x = 5? 3x + 15
    15·2 answers
  • What is the expand form for 0.632
    5·1 answer
  • Which of the following represents exponential growth?
    13·2 answers
  • Lydia is an architect. She has to design a courtyard garden inside a new hotel. On her blueprint, which is 1/24 the size of the
    15·1 answer
  • 4x-3=x+12 can anyone pls solve this im new to these type of maths i dont know how to do it
    15·2 answers
  • 37:28
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!